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nata0808 [166]
3 years ago
13

Question 10

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

56.8 g

Explanation:

Your first conversion factor is the molar mass of H2O to convert from grams of water to moles. Your second conversion factor is the mole ratio of 2 mol C2H10 for every 10 mol H2O. Your last conversion factor is the molar mass of C2H10 to convert from moles back to grams.

150. g H2O • (1 mol H2O / 18.02 g H2O) • (2 mol C2H10 / 10 mol H2O) • (34.1 g C2H10 / 1 mol C2H10) = 56.8 g C2H10

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A proton in a linear accelerator has a de Broglie wavelength of 132 pm. What is the speed of the wavelength?
kherson [118]

Answer:

The speed of wavelength is 3.0 ×10³ m/s.

Explanation:

Given data:

De Broglie wavelength = 132 pm (132×10⁻¹² m)

Speed of wavelength = ?

Solution:

Formula:

λ = h/mv

λ = wavelength

h = planck's constant

m = mass of proton

v = speed

now we will put the values in formula.

132×10⁻¹² m = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × v

v =  6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

j = kg m²/s²

v = 6.63 ×10⁻³⁴ kg m²/s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m

v = 6.63 ×10⁻³⁴ kg m²/s / 220.44 ×10⁻³⁹ kg.m

v = 0.03×10⁵ m/s

v = 3.0 ×10³ m/s

The speed of wavelength is 3.0 ×10³ m/s.

3 0
4 years ago
Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) 2Hg (l) + O
diamong [38]

hey there!:

2HgO (s) =>  2Hg (l) + O2 (g)

2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.

So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.

603 g of Hg = 603 / 200.6 = 3 moles

Percent yield = ( actual yield / theoretical yield) * 100

= ( 3/4) * 100

= 75 %

Hope this helps!

7 0
3 years ago
Read 2 more answers
Calculate the amount of heat gained by the water in cup 2 after adding the hot object(s) to it.
Iteru [2.4K]

Answer:

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

Explanation:

As we know

Amount of heat gained

Q = mc (T2-T1)

Here,

mass of water in cup 2 (m) = 79.10 grams

Temperature of water in cup 2 = 16.8 degree Celsius

Specific heat of water (c) = 4.186 J/(g °C)

Final Temperature of water in cup 2  = 23.2 degree Celsius

Substituting the given values, we get -

Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

3 0
3 years ago
A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M

C = 0.100 M

2.94=-log(\sqrt{k_a\times 0.100})

\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94

\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}

k_a=1.3\times 10^{-5}

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3 years ago
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4 years ago
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