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Elina [12.6K]
2 years ago
5

That light has a dual nature is referring to light: having energy and momentum. having high- or low-energy photons. acting as wa

ves and particles. undergoing pair production.
Physics
1 answer:
zloy xaker [14]2 years ago
5 0

Answer:

Option C, acting as waves and particles

Explanation:

Light has dual nature  because it acts both as a wave and particle. It has high energy particle i.e photons and it also behave as an electromagnetic wave. This property of light is studied under the quantum mechanics. Einstein also proved that light is a stream of photons possessing both electrical and magnetic properties.

Hence, option C is correct

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Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at t
slava [35]

Answer:

Part A

1) At the starting point, we have;

PE = 40,000 J

2) PE = 0 J, KE = 40,000 J

3) KE = 20,000 J

4) PE = 15,000 J

5) KE = 32,500 J

6) KE = 40,000 J, PE = 0 J

7) KE = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The total Mechanical Energy = ME = 40,000 J

At the final point, we have;

ME = KE + PE = 40,000 J + 0 J = 40,000 J

Explanation:

Part A

By the law of conservation of energy, we have;

ME = PE + KE

Where;

ME = The total Mechanical Energy of the system

PE = The Potential Energy of the system

KE = The Kinetic Energy of the system

Where there is no friction, we have;

At the final stage, KE = 40,000 J. PE = 0 J

Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J

1) At the starting point, we have;

KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J

2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;

PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J

3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J

4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J

5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J

6) At the bottom KE = 40,000 J, PE = 0 J

7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;

ME = KE + PE

At the final point, we have;

ME = 40,000 J + 0 J = 40,000 J

The total Mechanical Energy = ME = 40,000 J

8 0
2 years ago
0.180-kg stone rets on a frictionless, horizontal surface. A bullet of mass 7.50 g, traveling horizontally at 390 m/s, strikes t
Musya8 [376]

Answer:

The magnitud of the velocity is

8.46m/s

and the direccion:

-28.3 degrees from the horizontal.

Explanation:

Fist we define our variables:

m_{s}=0.18kg\\m_{b}=7.5g = 0.0075kg\\v_{1b}= 390m/s -i\\v_{1s}=0m/s\\v_{2b}=210m/s -j\\v_{2s}=?

The letters i and j represent the direction of the movement, i in this case is the horizontal direction, and j is perpendicular to i.

velocities with sub-index 1 are the speeds before the crash, and with sub-index 2 are the velocities after the crash.

Using conservation of momentum:

m_{s}v_{1s}+m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}\\v_{1s}=0, so\\m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}

Clearing for the velocity of the stone after the crash:

v_{2s}=\frac{m_{b}v_{1b}-m_{b}v_{2b}}{m_{s}}

Substituting known values:

v_{2s}=\frac{0.0075kg(((390m/s-i)-210m/s-j)}{0.18kg}\\v_{2s}=(16.25m/s-i) - (8.75m/s-j)

The magnitud of the velocity is :

|v_{2s}|=\sqrt{(16.25m/s-i)^2 + (8.75m/s-j)^2}\\|v_{2s}|=18.46m/s

and the direction:

tan^{-1}(-8.75/16.25)=-28.3

this is -28.3 degrees from the +i direction or the horizontal direcction.

Note: i and j can also be seen as x and y axis.

3 0
3 years ago
What is most likely to happen during deposition?
Iteru [2.4K]

Answer:

a person appears at a specified time and place and gives sworn testimony

Explanation:

Hope this helps

6 0
2 years ago
A student mixes two clear liquids together. After a few minutes, a white powdery solid can be seen settling on the bottom of the
SIZIF [17.4K]

I think the answer is A, please lmk if that is incorrect!

4 0
3 years ago
Read 2 more answers
a steam engine work on its vicinity 285 k heat is released with the help of 225 c energy absorbed to the system what is the effi
zvonat [6]

The efficiency of steam engine is  26.66 %.

<h3>What is Efficiency?</h3>

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = (Qs -Qr) / Qs

Given is the heat supplied Qs = 225 Joules and heat rejected Qr =285 . then the work done is

W = 225 -225 = - 60 Joules

Efficiency η  = 60/225 x 100%

η = 26.66 %

Thus, the efficiency of the steam engine is  26.66 %.

Learn more about efficiency.

brainly.com/question/13828557

#SPJ2

8 0
1 year ago
Read 2 more answers
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