According to KE = (3/2)kT
reducing temperature, in KELVIN, by half, average KE is reduced by half.
Answer:
the tension in the part of the cord attached to the textbook is 7.4989 N
Explanation:
Given the data in the question;
As illustrated in the image below;
first we determine the value of the acceleration,
along vertical direction; we use the second equation of motion;
y = ut +
a
t²
we substitute;
0 m/s for u, 1.29 m for y, 0.850 s for t,
1.29 = 0×0.850 +
×a
×(0.850)²
1.29 = 0.36125a
a
= 1.29 / 0.36125
a
= 3.5709 m/s²
Now when the text book is moving with acceleration , the dynamic equation will be;
T₁ = m₁a
where m₁ is the mass of the text book ( 2.10 kg )
a
is the vertical acceleration ( 3.5709 m/s² )
so we substitute
T₁ = 2.10 × 3.5709
T₁ = 7.4989 N
Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N
Answer:
gravitational pull by earth and friction
Explanation:
When the ball is placed on tilted tale it starts rolling because of the force of gravity pulls it downward along the plane of table and frictional force produces torque which generate rotational motion as a result body will start rolling.
Push of the table will be used to generate frictional force f=μ.N