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faust18 [17]
3 years ago
11

Two rockets, A and B, approach the earth from opposite directions at speed 0.80c. The length of each rocket measured in its rest

frame is 100 m. What is the length of rocket A as measured by the crew of rocket B?
Physics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

The contracted length as measured is 22.22 m

Solution:

As per the question:

Speed of the rockets, v = 0.8c

Length of the rocket, L =  100 m

Now,

To calculate the length of rocket A w.r.t rocket B:

The relative speed of the rockets A and B approaching the earth from the opposite directions:

Relative speed,\ v_{r} = \frac{- 0.8c - 0.8c}{1 + \frac{v^{2}}{c^{2}}}

v_{r} = \frac{- 1.6c}{1 + \frac{(0.8c)^{2}}{c^{2}}} = 0.975c

The contracted length is given by:

L' = \frac{L}{\sqrt{1 - \frac{v_{r}^{2}}{c^{2}}}}

L' = \frac{100}{\sqrt{1 - \frac{(0.975c)^{2}}{c^{2}}}} = 22.22\ m

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5 0
3 years ago
Match each term with the appropriate definition.
Ratling [72]

Answer:

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8 0
3 years ago
A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power.​
nata0808 [166]

A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power...

Solution,

displacement = 20 m

time = 10 sec

force = 500 N

work done = ?

power = ?

Now ,

work done = f × s

= 500 N × 20 m

= 10000 j

Now ,

power \:  =  \frac{w}{t}  \\  =  \frac{10000j}{10sec}  \\   = 1000W

~nightmare 5474~

8 0
3 years ago
Read 2 more answers
How long does it take a 22 kW steam engine to do 5.6 × 107 J of work? Answer in units of s.
Lena [83]
<h2>Time needed is 2545.45 seconds.</h2>

Explanation:

We know equation for power

               \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}

Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.

So

        Work = 5.6 × 10⁷ J

        Power = 22 kW = 22 x 10³ W

Substituting

        \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}\\\\22\times 10^3=\frac{5.6\times 10^7}{\texttt{Time}}\\\\\texttt{Time}=2545.45s

Time needed is 2545.45 seconds.

5 0
3 years ago
A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?
Ne4ueva [31]
<h3>Answer:  10 kg</h3>

==================================================

Work Shown:

We have these variables

  • p = momentum = 25 kg*m/s
  • m = mass = unknown
  • v = velocity = 2.5 meters per second

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

6 0
2 years ago
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