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faust18 [17]
3 years ago
11

Two rockets, A and B, approach the earth from opposite directions at speed 0.80c. The length of each rocket measured in its rest

frame is 100 m. What is the length of rocket A as measured by the crew of rocket B?
Physics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

The contracted length as measured is 22.22 m

Solution:

As per the question:

Speed of the rockets, v = 0.8c

Length of the rocket, L =  100 m

Now,

To calculate the length of rocket A w.r.t rocket B:

The relative speed of the rockets A and B approaching the earth from the opposite directions:

Relative speed,\ v_{r} = \frac{- 0.8c - 0.8c}{1 + \frac{v^{2}}{c^{2}}}

v_{r} = \frac{- 1.6c}{1 + \frac{(0.8c)^{2}}{c^{2}}} = 0.975c

The contracted length is given by:

L' = \frac{L}{\sqrt{1 - \frac{v_{r}^{2}}{c^{2}}}}

L' = \frac{100}{\sqrt{1 - \frac{(0.975c)^{2}}{c^{2}}}} = 22.22\ m

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You attach a meter stick to an oak tree, such that the top of the meter stick is 2.27 meters above the ground. later, an acorn f
Alexandra [31]

The acorn was at a height of <u>4.15 m</u> from the ground before it drops.

The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.

Calculate the speed of the acorn at the top of the scale, using the equation of motion,

s=ut+ \frac{1}{2} at^2

Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.

Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).

s=ut+ \frac{1}{2} at^2\\ (2.27 m)=u(0.301s)+\frac{1}{2}(9.8m/s^2)(0.301s)^2\\ u=\frac{1.8261m}{0.301s} =6.067m/s

If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.

Use the equation of motion,

v^2=u^2+2as

Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.

v^2=u^2+2as\\ (6.067m/s)^2=(0m/s)^2+2(9.8m/s^2)h_2\\ h_2=\frac{(6.067m/s)^2}{2(9.8m/s^2)} =1.878 m

The height h above the ground at which the acorn was is given by,

h=h_1+h_2=(2.27 m)+(1.878 m)=4.148 m

The acorn was at a height <u>4.15m</u> from the ground before dropping down.

3 0
3 years ago
Static electricity occurs when two objects have different electrical charges. When objects are rubbed together, the electrons fr
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Explanation:hope that helps

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How much electrical energy is used by a 400 W toaster that is operating for 5 minutes?
Shkiper50 [21]

The electrical energy consumed by a toaster is 0.033 Kwh.

<u>Explanation</u>:

The power utilized by the toaster is 400 W.

\text { The power utilized by the toaster is } 400 \mathrm{W} \text { in kilo-watts is } \frac{400}{1000}=0.4 \mathrm{Kw}

The toaster is operated for 5 Minutes.

\text { The toaster is operated for } 5 \text { Minutes in hours is } \frac{5}{60}=0.083 \text { hours. (One minute is } 60 \text { seconds) }

We know that,

\text {power}=\frac{\text {energy}}{\text {time}}

Substitute the values in the above formula to obtain electrical energy,

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Electrical energy = 0.4 × 0.083

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3 years ago
Will the 79 kg skier in the figure below slide down if f the coefficient of static friction is 0.25?
mariarad [96]

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down

4 0
3 years ago
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