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Arturiano [62]
3 years ago
8

Choose the law each sentence describes. This law relates a planet's orbital period and its average distance to the Sun. The orbi

ts of planets are ellipses with the Sun at one focus. The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames.
Physics
2 answers:
Leviafan [203]3 years ago
8 0

Explanation:

Kepler's has given three laws as :

1. Kepler's first law - It is also known as law of ellipses. This law states that the planets revolves around the sun in an elliptical orbit.

2. Kepler's second law - It is also known as law of equal areas. This law states that the line that connects the planet and the sun covers equal areas in equal interval of time.

3. Kepler's third law - It is also known as law of law of harmonics. This law states that the square of orbital time period is directly proportional to the cube of the average distance from the sun i.e. T^2\propto a^3  

hram777 [196]3 years ago
7 0

These are the Kepler's laws of planetary motion.

This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.

The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.

The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.

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An attacker at the base of a castle wall 3.65 m high throws a rock straight up with speed 7.4m/s from a height of 1.55m above th
Natali5045456 [20]

a) Yes, the rock will reach the top

b) The final speed is 3.7 m/s

c) The change in speed is 2.4 m/s

d) The change in speed in the two situations do not agree

e) Because the kinetic energy depends quadratically on the speed, K\propto v^2

Explanation:

a)

The mechanical energy of the rock at the moment it is thrown from the ground is equal to the sum of its kinetic energy and its potential energy:

E=KE_i + PE_i = \frac{1}{2}mu^2 + mgh_i

where

m is the mass of the rock

u = 7.4 m/s is the inital speed

g=9.8 m/s^2 is the acceleration of gravity

h_i = 1.55 m is the initial height of the rock

Substituting, we find the initial mechanical energy of the rock

E=\frac{1}{2}m(7.4)^2 + m(9.8)(1.55)=42.6m [J]

In order to reach the top of the castle, the rock should have a mechanical energy of at least

E' = mgh'

where

h' = 3.65 m is the heigth of the top

Substituting,

E'=m(9.8)(3.65)=35.6m [J]

Since E > E', it means that the rock has enough mechanical energy to reach the top.

b)

The final mechanical energy of the rock at the top is

E=mgh'+ \frac{1}{2}mv^2 (1)

where:

v is the final speed of the rock at the top

Since the mechanical energy is conserved, this should be equal to the initial mechanical energy:

E=42.6 m [J] (2)

Therefore, equating (1) and (2), we can find the final speed of the rock:

mgh' + \frac{1}{2}mv^2 = 42.6m\\v=\sqrt{2(42.6-gh')}=\sqrt{2(42.6-(9.8)(3.65))}=3.7 m/s

c)

Since the motion of the rock is a free fall motion (constant acceleration equal to the acceleration of gravity), we can use the following suvat equation:

v^2 - u^2 = 2as

where

v is the final speed, at the bottom

u = 7.4 m/s is the initial speed of the rock, at the top

a=9.8 m/s^2 is the acceleration of gravity

s = 3.65 - 1.55 = 2.1 m is the vertical displacement of the rock

Solving for v, we find the final speed:

v=\sqrt{u^2+2as}=\sqrt{7.4^2 + 2(9.8)(2.1)}=9.8 m/s

Therefore, the change in speed is

\Delta v = v-u = 9.8 - 7.4 =2.4 m/s

d)

In the first situation (rock thrown upward), we have:

u = 7.4 m/s (initial speed)

v = 3.7 m/s (final speed)

So the change in speed is

\Delta v = v-u =3.7 - 7.4 = -3.7 m/s

While the change in speed in the second situation (rock thrown downward) is

\Delta v = 2.4 m/s

Therefore, we see that their magnitudes do not agree.

e)

In both situations, the change in kinetic energy of the rock is equal in magnitude to the change in gravitational potential energy, since the total mechanical energy is conserved.

The change in gravitational potential energy in the two situations is the same (because the change in height is the same), therefore the change in kinetic energy in the two situations is also the same.

However, the kinetic energy of the rock is not directly proportional to the speed, but to the square of the speed:

K\propto v^2

Since the initial speed is the same for both situation (7.4 m/s), but the change in kinetic energy has opposite sign in the two situations (negative when the rock is thrown upward, positive when thrown downward), the situation is not symmetrical, therefore in order to have the same magnitude of change in the kinetic energy, the change in speed must be larger when the kinetic energy involved is lower, so in the first situation.

Learn more about kinetic energy and about potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
4 years ago
Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope
mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

       Em₀ = U = m g y

Lowest point

     Em_{f} = K = ½ m v²

As there is no friction, mechanical energy is conserved

       Em₀ = Em_{f}

       m g y = ½ m v²

       v = √ 2 g y

Where we can use trigonometry to find and

       sin 30 = y / L

       y = L sin 30

Let's replace

      v = RA (2 g L sin 30)

Let's calculate

      v = RA (2 9.8 100.0 sin30)

      v = 31.3 m / s

4 0
3 years ago
Is work done in this example: A student lifting a heavy backpack off of the floor.
vagabundo [1.1K]
I don't know what u mean
4 0
3 years ago
Read 2 more answers
Why the temperature of a resistor increase when a current pass through it
Kazeer [188]

Answer:

So, when an electrical charge passes through a resistor, some of that electrical energy is transferred into heat, increasing the temperature. This extra energy causes the particles in the resistor to vibrate more. With these particles moving more, it is more difficult to for the electrons to move through the resistor.

4 0
3 years ago
Calculate the frequency of each of the following wave lengths of electromagnetic radiation. Part A 488.0 nm (wavelength of argon
Drupady [299]

Answer:

A. f=6.1475*10^{14}Hz

B. f=5.9642*10^{14}Hz

Explanation:

The frequency has an inversely proportional relationship with the concept of wavelength, the greater the wavelength, the lower the frequency. For electromagnetic waves, the frequency is equal to the speed of light, divided by the wavelength.

f=\frac{c}{\lambda}

A.

f=\frac{3*10^8\frac{m}{s}}{488*10^{-9}m}\\\\f=6.1475*10^{14}Hz

B.

f=\frac{3*10^8\frac{m}{s}}{503*10^{-9}m}\\\\f=5.9642*10^{14}Hz

7 0
4 years ago
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