Question

In a first-order reaction, the half-life is 139 minutes. What is the rate constant?

Answer 1

Answer:

a. 8.31 x 10-5 s-1

Explanation:

The general first-order reaction is:

ln[A] = ln[A]₀ -kt

Where [A] is acutal concentration of reactant, initial concentration is [A]₀, k is rate constant and t is time pass

And the equation of the half-life, t 1/2, is:

$t_{1/2} = \frac{ln 2}{K}$

Has half-life is 139min:

139min * (60s / 1min) = 8340s

$t_{1/2} = \frac{ln 2}{8340s}$

Half-life is 8.31x10⁻⁵ s⁻¹

a. 8.31 x 10-5 s-1