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Andrej [43]
2 years ago
8

Choose a property of matter and research how this property affects the way matter interacts with the world around it. Find out h

ow the property is useful in nature or how humans make use of it.
What does this property describe?

How does the property differ between different types of matter?

Is this property used in any technology or by nature in any way?
Record your research.

NEED HELP RIGHT NOW!!!!

Chemistry
1 answer:
goblinko [34]2 years ago
8 0

Answer:

Liquid foundation is a property it describes solutions, volume. weight is a property from the monocules in lighter than air. which is a natural way to simplify systematic independence. for science. Onced liquid forms a mass of ascetain size it would be used for more technology. Differences in property which are properties: oxegenation. temeratures, measurements. maybe to form independant examples.

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Consider the following data:
VikaD [51]

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

ΔHf H₂O = -241.82 kJ/mol

ΔHf  C₂H₆ = - 84.68 kJ/mol

Reaction

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Required

ΔHrxn=

Solution

<em>∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants) </em>

∆H ° rxn = (4.-393.5+6.-241.82)-(2.-84.68)

∆H ° rxn = (-1574-1450.92)-(-169.36)

∆H ° rxn =-3024.92+169.36

∆H ° rxn =-2855.56 kJ

8 0
3 years ago
Read 2 more answers
2. Sitting on a bench top are several samples: lithium metal (d = 0.53 g/mL), gold (d = 19.3 g/mL), aluminum (d = 2.70 g/mL), an
Snezhnost [94]

Answer:

The sample of lithium occupies the largest volume.

Explanation:

Given the densities for the four elements, we have the expression d=\frac{m}{V} that shows the relationship between mass and Volume to express the density of an element.

For each element we have:

d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL

d_{gold}=\frac{m_{gold}}{V_{gold}}=19.3g/mL

d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL

d_{lead}=\frac{m_{lead}}{V_{lead}}=11.3g/mL

The problem says that all the samples have the same mass, so:

m_{lithium}=m_{gold}=m_{aluminum}=m_{lead}=m

it means that m is a constant

Now, solving for the Volume in each element and with m as a constant, we have:

V_{lithium}=\frac{m}{d_{lithium}}

V_{lithium}=\frac{1}{0.53\frac{g}{mL}} *m

V_{lithium}=1.88\frac{mL}{g}*m

V_{gold}=\frac{m}{d_{gold}}

V_{gold}=\frac{1}{19.3\frac{g}{mL}} *m

V_{gold}=5.18*10^{-2}\frac{mL}{g}*m

V_{aluminum}=\frac{m}{d_{aluminum}}

V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m

V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m

V_{lead}=\frac{m}{d_{lead}}

V_{lead}=\frac{1}{11.3\frac{g}{mL}} *m

V_{lead}=8.85*10^{-2}\frac{mL}{g}*m

If we assume m = 1g, we find that:

V_{lithium}=1.88mL

V_{gold}=5.18*10^{-2}mL

V_{aluminum}=3.70*10^{-1}mL

V_{lead}=8.85*10^{-2}mL

So we can see that the sample of lithium occupies the largest volume with 1.88mL

Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.

4 0
2 years ago
What types of elements join to form molecular compounds? Name three such compounds
Charra [1.4K]

Answer:

NO nitrogen monoxide

N2O dinitrogen monoxide

S2Cl2 disulfur dichloride

Explanation:

4 0
2 years ago
Read 2 more answers
75.0 grams NaBr<br> Find the molar mass and number of moles
AVprozaik [17]

Answer:

Molar mass = 103.0 g/mol,

0.728 mol NaBr

Explanation:

Molar mass M(NaBr) = M(Na) + M(Br) = 23.0 + 80.0 = 103.0 g/mol

75.0 g NaBr * 1 mol NaBr/103.0 g NaBr=0.728 mol NaBr

7 0
3 years ago
If a 65 kilogram student exerts a force with a magnitude of 100 N on a 100 kilogram desk the magnitude of the force that the des
mrs_skeptik [129]
C. The action/reaction law states that a force is equal in both directions.
4 0
3 years ago
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