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Andrej [43]
2 years ago
8

Choose a property of matter and research how this property affects the way matter interacts with the world around it. Find out h

ow the property is useful in nature or how humans make use of it.
What does this property describe?

How does the property differ between different types of matter?

Is this property used in any technology or by nature in any way?
Record your research.

NEED HELP RIGHT NOW!!!!

Chemistry
1 answer:
goblinko [34]2 years ago
8 0

Answer:

Liquid foundation is a property it describes solutions, volume. weight is a property from the monocules in lighter than air. which is a natural way to simplify systematic independence. for science. Onced liquid forms a mass of ascetain size it would be used for more technology. Differences in property which are properties: oxegenation. temeratures, measurements. maybe to form independant examples.

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The equilibrium fraction of lattice sites that are vacant in silver (ag) at 500°c is 0.5 x 10-6. calculate the number of vacanci
Sedbober [7]
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6 0
3 years ago
3. Methyl acetate is hydrolyzed at 25 oC in acidic environment. Aliquots of equal volume are removed and titrated with NaOH solu
avanturin [10]

Solution :

Time (sec)       Volume of NaOH (mL)

339                           26.23

1242                         27.80

2745                        29.70

4546                         3.81

$\infty$                               39.81

Now the example of the first order kinetics w.r.t volumetric analysis is :

$k=\frac{2.303}{t} \log \left(\frac{v_{\infty}-v_0}{v_{\infty}- v_t}\right)$

Here, $v_{\infty}= \text{ volume at }\infty = 39.81$

$v_{t}= \text{ volume at time 't' } = 27.80$

$v_0$ = volume at time 0 = 0

Since the interval is not constant, we take the time interval as

$=\frac{903+1503+1801}{3}$

$=\frac{4207}{3}$

= 1402.3333

≈  1402 seconds

$k=\frac{2.303}{1402} \log \left(\frac{39.81-0}{39.81-27.80}\right)$

  $=(0.001643) \log \left(\frac{39.81}{10.01}\right)$

  = 0.001643 x 0.52045

  = 0.00082

  $= 8.55 \times 10^{-4} \ sec^{-1}$

Therefore, the first order rate constant is k $= 8.55 \times 10^{-4} \ sec^{-1}$.

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