Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
(f+g-k)(x) means to add the equations f(x) and g(x) then subtract k(x)
2x^2 + 3x + 4x - 9 = 2x^2 +7x -9
2x^2 + 7x - 9 - x^2 -7x = x^2 -9
The answer is : x^2 - 9
Answer:
And solving for the radius we got:
And replacing the data given we got:
And this value converted to meters is 
Step-by-step explanation:
For this case we know the population size 
and we also know the population density 
We can assume that the area is a circle. We also know that the formula for the population density is given by:
Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:
With X the radius of the circle
And then the populationd density become:
And solving for the radius we got:
And replacing the data given we got:
And this value converted to meters is
A. d=45t
b. 112.5 miles. 112.5=45•2.5
The answer is C. If you have any questions then leave a comment. Good luck!
