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Ilya [14]
3 years ago
13

Why do you think the cart rolls farther when it starts from a higher position?

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0

Answer:

It has higher PE which can be converted into kinetic energy. The car also has had more work done on it when its at a higher position.

Step-by-step explanation:

yuradex [85]3 years ago
6 0

This is because the cart gains speed as it goes from the top of higher point to bottom.

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What is the common difference of the sequence below?
vagabundo [1.1K]

Answer:

Step-by-step explanation:

In finding the COMMON DIFFERENCE, subtract the 2nd term and the first term.

a1 = -4

a2 = -2

Let "d" representing the COMMON DIFFERENCE.

d = -2 -(-4)

d = -2 + 4

d = 2

ANSWER:

THE COMMON DIFFERENCE OF THIS SEQUENCE IS 2

3 0
3 years ago
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Can you put 150 177 205 163 172 190 186 168 155 in order
Eduardwww [97]
150, 155, 163, 168, 172, 177, 186, 190, 205
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3 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
4 years ago
Math please help me with it
seropon [69]
I hope this helps you

4 0
4 years ago
5 g of margarine contains 3.6 g
Komok [63]

Answer:

59.04g of fat

Step-by-step explanation:

I) Figure out how much grams of fat is in 1g of margarine:

3.6 ÷ 5 = 0.72

II) Next, we can figure out how much fat is in 82 g of margarine:

0.72 × 82 = 59.04

One shot formula:

(3.6g ÷ 5g) × 82g = 59.04g

8 0
3 years ago
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