Answer:
10.1 g of Al are formed
Explanation:
The reaction is:
2AlCl3 --> 2Al + 3Cl2
So 2 moles of aluminun chloride decompose into 2 moles of Al and 3 moles of chlorine.
Ratio is 2:2.
Let's convert the mass of salt into moles (mass / molar mass)
50 g / 133.34 g/mol = 0.374 moles.
As the ratio is 2: 2, if I have 0.374 moles of salt, I would produce the same amount of Al, just 0.374.
Let's convert the moles to mass
(Mol . molar mass)
0.374 mol . 26.98 g / mol = 10.1 g of Al are formed
Ξ
All pieces will be 17 g/cm^3 because the density is not affected by cutting (assuming the rock is uniform).
Solution :
From Fick's law:
Mass balance: Exits = Accumulation
From the last step, area cancels out and thus leaves :
So now we can substitute the 
by the Fick's law
Substituting the values we get
the most stable monatomic ion formed from aluminum is Al^{3+}
