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Anna11 [10]
3 years ago
9

Do You Know That If you put a Grape in the microwave it will go on Fire!?

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

really?!?! well did u know oranges can get stale??

You might be interested in
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
3 years ago
A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th
tatyana61 [14]

Answer : The partial pressure of the CO_2 in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % CO_2 and 25 % N_2 in terms of volume.

First we have to calculate the moles of CO_2 and N_2.

\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole

\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole

Now we have to calculate the mole fraction of CO_2.

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}

\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75

Now we have to calculate the partial pressure of the CO_2 gas.

\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}

\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the CO_2 in the tank in psia is, 32.6 psia.

3 0
3 years ago
In 1–2 sentences, explain why weather can be predicted only as probable, not definite.
MAVERICK [17]

Answer:

Meteorologists use computer models to predict the weather. And computational power has come an extended way. Yet meteorologists still have trouble correctly predicting the weather over some days. Sometimes they don’t even comprehend right over 24 hours! Why does this happen? Their ability to predict the weather is restricted by the number of available data, the time available to research it, and therefore the complexity of weather events.

Explanation:

6 0
3 years ago
1. If a car is traveling 90 mi/hr, how many feet will the car travel in 1 sec? In 5 sec?
Fudgin [204]

Answer:

The car travel 660 feet

Explanation:

First convert the Speed into <u>Feet/sec</u>

Speed of the car = 90 mi/hr

1 mi = 5280 ft

In 90 miles = 90 x 5280 = 475,200  feet

1 hr = 60 min

1 min = 60 sec

So ,

1 hr = 60 x 60 sec = 3600 sec

The speed is defined as the distance traveled by the object in unit time. The formula of speed is :

Speed =\frac{distance}{time}

Speed =\frac{90mi}{1hr}... given

Speed =\frac{475200 ft}{3600sec}

Speed = 132 ft/sec

Now,  time = 5 sec

Speed =\frac{distance}{time}

distance =speed\times time

distance = 132ft/sec\times 5sec

Distance = 660 feet

3 0
3 years ago
Calculate the volume occupied by 32.0 g of O2 gas, the pressure of the O2 gas is 78.5 kPa at 25°C.
Oksi-84 [34.3K]

Answer: 31.5L

Explanation:

6 0
3 years ago
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