Answer:
2.7005 g/cm²
explanation: as we know density=mass/volume
1,05+ 0,69 + 1,82 = 3,56g of mixture
%CaCO₃: 1,82/3,56×100% = 0,5112×100% = 51,12%
The molarity of NaOH needed is calculated as follows
calculate the moles of KhC8h4O4
that is moles = mass/molar mass of KhC8h4O4(204.22 g/mol)
=0.5632g /204.22g/mol= 2.76 x10^-3 moles
write the equation for reaction
khc8h4O4 + NaOH ---> KNaC8h4O4 + H2O
from the equation above the reacting ratio of KhC8h4O4 to NaOh is 1:1 therefore the moles of Naoh is also 2.76 x10^-3 moles
molarity of NaOh = (moles of NaOh / volume ) x 1000
that is { (2.76 x10^-3) / 23.64} x100 =0.117 M
3079.23 is what you get when you multiply the answers.
