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anyanavicka [17]
3 years ago
10

11 times 4 and 1 3rds

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0
11×4\frac{1}{3}

\frac{11}{1}×\frac{13}{3}
You multiply across
\frac{143}{3}
You divide the numerator(top) by the denominator(bottom)
\frac{143}{3} =47 \frac{2}{3}

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Goals scored by a hockey team in successive matches are 5,7,4,2,4,0,5,5 and 3. What is the number of goals, the team must score
Stels [109]

Answer:

5

Step-by-step explanation:

Total goals /total no. of matches = 4

5+7+4+2+4+0+5+5+3+x / 10 = 4

35 + x = 4 × 10

x = 40 - 35

x = 5

So, the team must score 5 inorder to get the average of 4 goals per match.

6 0
2 years ago
What are the differences between an (Algebraic) equation and expression?
lara31 [8.8K]

Hello!


An equation has an (=). They equal something. For example, 1+1=2 is an equation.


An expression does not have an equal sign. For example, 2 or 1+3 are both expressions. They have no equal sign.


I hope this helps!

6 0
2 years ago
12.20h - 7.15 = 90.45
zhannawk [14.2K]

Answer:

H=8

Step-by-step explanation:

12.2H-7.15=90.45

12.2H=90.45+7.15

12.2H=97.6

H=8

6 0
2 years ago
Read 2 more answers
JK = 7x + 9<br> JL = 114, and<br> KL = 9x + 9,<br> Find KL.
VikaD [51]

Answer:

KL= 63

Step-by-step explanation:

JK=7x+9 , JL=114 , KL=9x+9 ( if the points are on the same line and point J at the end point and K in the middle)

*J_______________________K___________________________L

JL=JK+KL

114=7x+9+9x+9

114-18=16 x

16x=98

x=98/16=6

KL= 9x+9

KL=9(6)+9

KL= 63

8 0
3 years ago
Check the true statements below:
valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d.  In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0
3 years ago
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