Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = 
= sin θ
sin θ = y / L
we substitute
= m λ
with the initial data we look for the distance between the lines
d = 
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Exons And Introns differ because Exons code for protein and Introns do not.
so your answer would be: Exons code for Proteins
Are you in K12?
Answer:
The centripetal acceleration of the object is 
.
Explanation:
We have,
Radius of a circular path is 200 m
It takes 5 seconds to complete 10 revolutions. The angular velocity of the object is given by the rate of change of angular displacement per unit time :
The centripetal acceleration of the object is given by :
So, the centripetal acceleration of the object is .
Answer:
The angle of projection is 12.26⁰.
Explanation:
Given;
initial position of the dart, h₀ = 1.50 m
height above the ground reached by the dart, h₁ = 1.73 m
maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m
velocity of the dart, u = 10 m/s
The maximum height reached by the projectile is calculated as;
where;
θ is angle of projection
g is acceleration due to gravity = 9.8 m/s²
Therefore, the angle of projection is 12.26⁰.
