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Strike441 [17]
3 years ago
5

What is analogy a powerful rhetorical device?

Physics
1 answer:
wolverine [178]3 years ago
5 0
The other person who answered this is wrong btw
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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters
Dmitry [639]
Work = Force * distance

He's going up an incline but pushing parallel to the ground. Draw out a diagram to show what's going on. )


Work =  force* distance*Cos(incline angle)
60 N force * 10 meters * cos(30)
= 519.61 J

7 0
4 years ago
What is the equation of universal law of garavitation
Vladimir79 [104]

Answer:

F= \frac{GmM}{ {r}^{2} }

G= gravitational constant

F= Gravitational force

m= mass of object 1

M= mass of object 2

r= distance between two objects

5 0
3 years ago
A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 meters above the ground
Alexus [3.1K]

Answer:

Answer:

72.936 Joule

Explanation:

Mechanical Energy = Potential Energy + Kinetic Energy

Kinetic Energy = (1/2) x m x V² = (1/2) x 1.8 x 4.8² = 20.736 J

Potential Energy = m x g x h = 1.8 x 10 x 2.9 = 52.2 J

Total Mechanical Energy = 20.736 + 52.2 = 72.936 Joule

Explanation:

8 0
3 years ago
A loop of wire is placed in a uniform magnetic field. (a) For what orientation of the loop is the magnetic flux a maximum? The p
ra1l [238]

Answer:

1) The plane of the loop is perpendicular to the magnetic field.

2) The magnetic flux is independent of the orientation of the loop.p

Explanation:

The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.

5 0
3 years ago
A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper c
Zolol [24]

Answer:

150.8 J

Explanation:

The heat released by the copper wire is given by:

Q=mC_s \Delta T

where:

m = 10.0 g is the mass of the wire

Cs = 0.377 j/(g.C) is the specific heat capacity of copper

\Delta T=40.0 C - 80.0 C=-40.0 C is the change in temperature of the wire

Substituting into the equation, we find

Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J

And the sign is negative because the heat is released by the wire.

6 0
3 years ago
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