Answer:
magnification will be -0.025
Explanation:
We have given the radius of curvature = 12 cm
And object distance = 3 m
So focal length 
Now for mirror we know that
So 

v = 0.750 m
Now magnification of the mirror is 
No. Quatro cientos grads.
Answer:
275 kPa
Explanation:
mass of the gas=m=1.5 kg
initial volume if the gas=V₁=0.04 m³
initial pressure of the gas= P₁=550 kPa
as the condition is given final volume is double the initial volume
V₂=final volume
V₂=2 V₁
As the temperature is constant
T₁=T₂=T
=
putting the values in the equation.
=
P₂=
P₂=
P₂=275 kPa
So the final pressure of the gas is 275 kPa.
Each piece will have 1/4 of the mass of the original big cube, but its density will be the same.
Density is a property of a substance, no matter how much or how little of it you have.
A speck of it on the tip of your pinky and a supertankerful of the same substance have the same density.
I think it is 5% hope this helped