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tankabanditka [31]
2 years ago
14

A 0.85 kg soccer ball is booted straight up in the air. If it left the soccer player's foot at a height of 1.0 m and reaches a h

eight of 47.0 m, what was its kinetic energy immediately after it was kicked?​
Physics
1 answer:
Daniel [21]2 years ago
7 0

Answer:

383 J

Explanation:

m = 0.85 kg, h = 1.0 m, H = 47.0 m

Find KE at h

At h, total energy = KE + mgh

At H, KE = 0, total energy = mgH

Energy conservation:

KE + mgh = mgH

so KE = mgH - mgh = mg(H - h) = 0.85*9.8*(47.0-1.0) = 383 J

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2 years ago
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cluponka [151]

Answer:

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Doss [256]

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