A 0.85 kg soccer ball is booted straight up in the air. If it left the soccer player's foot at a height of 1.0 m and reaches a h
1 answer:
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We have that The ratio U1/U2 of their potential energies due to their interactions with Q is
From the question we are told that
Question 1
Charge q1 is distance r from a positive point charge Q.
Question 2
Charge q2=q1/3 is distance 2r from Q.
Charge q1 is distance s from the negative plate of a parallel-plate capacitor.
Charge q2=q1/3 is distance 2s from the negative plate.
Generally the equation for the potential energy is mathematically given as
Therefore
The Equations of U1 and U2 is
For U1
For U2
Since
U is a function of q and q2=q1/3
Therefore
For Question 2
For U1
Therefore
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Answer:
Speed: 4.8 m/s
Velocity: 4.8 m/s north
Explanation:
Definitions:
- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):
- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:
And it also has a direction (the same as the displacement).
In this problem:
- The object travels a distance of
d = 105 m
In a time interval of
t = 22 s
So its speed is
- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:
However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.