The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
<u>Explanation:</u>
Given data,
E= 3 ×10 ⁶ Δx=0.06/100
We have to find the minimum potential difference
E= -ΔV/Δx
ΔV=- E × Δx
ΔV =-3 ×10 ⁶ . 0.06/100
ΔV=-1800 V
The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
Resistor. The answer is a resistor. They do not transmit electricity.
Answer:
A) i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Explanation:
Given data :
Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol
A) Calculate the critical extents of reaction for gelation
i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
attached below is the detailed solution
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Answer:
speed wind Vw = 54.04 km / h θ = 87.9º
Explanation:
We have a speed vector composition exercise
In the half hour the airplane has traveled X = 108 km to the west, but is located at coordinated 119 km west and 27 km south
Let's add the vectors in each coordinate axis
X axis (East-West)
-Xvion - Xw = -119
Xw = -Xavion + 119
Xw = 119 -108
Xwi = 1 km
Calculate the speed for time of t = 0.5 h
Vwx = Xw / t
Vwx= 1 /0.5
Vwx = - 2 km / h
Y Axis (North-South)
Y plane - Yi = -27
Y plane = 0
Yw = 27 km
Vwy = 27 /0.5
Vwy = 54 km / h
Let's use the Pythagorean theorem and trigonometry to compose the answer
Vw = √ (Vwx² + Vwy²)
Vw = R 2² + 54²
Vw = 54.04 km / h
tan θ = Vwy / Vwx
tan θ = 54/2 = 27
θ = Tan⁻¹ 1 27
θ = 87.9º
The speed direction is 87. 9th measure In the third quadrant of the X axis in the direction 90-87.9 = 2.1º west from the south