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Margarita [4]
3 years ago
6

What voltage is required to move 2A through 5Ω?

Physics
1 answer:
Burka [1]3 years ago
4 0
10
Explanation: V=AxR
2x5 (2 times five)
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Beginning at time t = 0, a student exerts a horizontal force on a box of mass 30 kg, causing it to move at 1.2 m/s toward an ele
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Since the initial and the final velocity are just equal, it is implied that the acceleration is zero. This means that the net force acting on the body is also zero. The horizontal force should be equal to the force of friction. The force of friction is equal to the product of the coefficient and the normal force. 
                               

 Ff = (coefficient of friction) x Fn


The normal force is equal to the object's weight if the surface is horizontal.


                               Ff = (0.20) x (30 kg) x (9.8 m/s²)  = 58.8 N
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<span>Thus, the horizontal force exerted must be 58.8 N. 

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago
What do you guys know about emotional intelligence? And how is it used in the real world?
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7 0
3 years ago
Mae prefers to complete graphs or charts to show the information she has learned. What kind of learner is Mae likely to be?
yan [13]

Answer:

Prob. D

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3 0
3 years ago
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You are in a contest with your friends to see who can drive a golf ball the farthest. should you hit a "line drive" (low to the
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Line drive would be more farthest from the very high angle shot because when we increase the angle of flight the range started to increase and at some point it becomes maximum and that angle is 45° after that as you go on increasing the angle it won't be covering more distance as compared to the max at (45°) .
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When hiking at altitude, the air pressure drops to 825,000Pa. Solve the force that site exerts against the side of a rectangular
OLga [1]

Answer:

The force is 1237500N

Explanation:

We can apply the following expression

pressure=\frac{Force}{Area}

To find the area of rectangular tent wall:

Area=length *width\\Area=2.00m*0.750m\\Area=1.5m^{2}

Now to find the force:

pressure=825,000pa

pressure=\frac{Force}{Area}

Force=pressure*Area\\Force=825000pa*1.5m^{2} \\Force=1237500N

7 0
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