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Lady_Fox [76]
3 years ago
9

Why air pollution is a problem?

Physics
1 answer:
Strike441 [17]3 years ago
8 0
1. Air pollution is a problem<span> because it can cause damage to animals, trees, plants, crops and water sources in the environment. </span>Pollution<span> in the </span>air<span> causes </span>problems<span> for aviation because it reduces visibility, while also being responsible for damaging buildings and other structures.
2. </span><span>The air we breathe has a very exact chemical composition; 99 percent of it is made up of nitrogen, oxygen, water vapor and inert gases. Air </span>pollution occurs<span> when things that aren't normally there are added to the air. A common type of air </span>pollution<span>happens when people release particles into the air from burning fuels.
3. </span>Pollution prevention (P2) is any practice that reduces, eliminates, or prevents pollution at its source. ... Reducing the amount of pollution produced means less waste to control, treat, or dispose of. Less pollution means less hazards posed to public health and the environment.
4. Why is it so important to have clean air? 
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A wave has a frequency of 440 hz and a wavelength of 0.77m. What is the velocity of the wave
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Answer:velocity of wave

=338.8 m/s

Explanation:

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3 years ago
A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work
I am Lyosha [343]

Answer:

\boxed {\boxed {\sf 157.5 \ Joules }}

Explanation:

Work is equal to the product of force and distance.

W=F*d

The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.

F= 45 \ N \\d= 3.5 \ m

Substitute the values into the formula.

W= 45 \ N * 3.5 \ m

Multiply.

W= 157.5 \ N*m

  • 1 Newton meter is equal to 1 Joule
  • Our answer of 157.5 N*m equals 157.5 J

W= 157.5 \ J

<u>157.5 Joules </u> of work are done on the crate.

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2 years ago
A centrifugal pump is operating at a flow rate of 1 m3/s and a head of 20 m. If the specific weight of water is 9800 N/m3 and th
tamaranim1 [39]

Answer:

<em>The power required by the pump is nearly 230.588 kW</em>

Explanation:

Flow rate of the pump Q = 1 m^3/s

the head flow H = 20 m

specific weight of water γ = 9800 N/m^3

efficiency of the pump η = 85%

First note that specific gravity of water is the product of the density of water and acceleration due to gravity.

γ = ρg

where ρ is density. For water its value is 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

The power to lift this water at this rate will be gotten from the equation

P = ρgQH

but ρg = γ

therefore,

P = γQH

imputing values, we'll have

P = 9800 x 1 x 20 = 196000 W

But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.

we can say that

196000 W is 85% of the power of the pump power needed, therefore

196000 = 85% of P_{p}

where P_{p} is the power of the pump needed

85% = 0.85

196000 = 0.85P_{p}

P_{p} = 196000/0.85 = 230588.24 W

<em>Pump power = 230.588 kW</em>

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