Explanation:
According to newtons first law of motion:
'' a body will continue in its state of rest or uniform motion along a path unless it is acted upon by an external force".
A body in equilibrium that is floating will be stable and not move in any direction. Even if it moves, the motion will be constant wouldn't change.
- To move the body in any direction, one has to swim.
- Swimming is the application of an external force to counter the balanced forces at equilibrium on a body.
- This works when the net external force is greater than that the balanced forces.
learn more:
Newton brainly.com/question/11411375
#learnwithBrainly
Answer:
K = 1800 kJ
Explanation:
Given that,
The speed of the object, v = 30 m/s
Mass of the object, m = 4000 kg
We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :
![K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5CK%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%204000%5Ctimes%2030%5E2%5C%5C%5C%5CK%3D1800000%5C%5C%5C%5Cor%5C%5C%5C%5CK%3D1800%5C%20kJ)
So, the required kinetic energy is equal to 1800 kJ.
Answer:
The answer is
A. Pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.
Explanation:
The question is incomplete, here is a complete question with full options
You are caulking a window. The caulk is rather thick and, to lay the bead correctly, the exit nozzle is small. A caulking gun uses a plunger which is operated by pulling back on a handle. You must squeeze the handle very hard to get the caulk to come out of the narrow opening because:_________.
A. pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.
B. viscous drag between the walls of the tip and the caulk causes the caulk to swirl around chaotically.
C. Newton’s third law requires most of the energy in the caulk to be used to push back on the plunger rather than moving it through the tip.
D. the high density of the caulk impedes its flow through the small opening.
Since the caulk is thick and the exit nozzle is small, the pressure needed to deliver the caulk will be very high as pressure is uniformly distributed at the plunger side at every part of the caulk, hence very high pressure is needed to deliver the caulk which is why the handle needed the very hard squeeze
Answer:
The ball traveled 0.827 m
Explanation:
Given;
distance between the metal plates of the room, d = 3.1 m
mass of the glass, m = 1.1g
charge on the glass, q = 4.7 nC
speed of the glass ball, v = 4.8 m/s
voltage of the ceiling, V = +3.0 x 10⁶ V
The repulsive force experienced by the ball when shot to the ceiling with positive voltage, can be calculated using Coulomb's law;
F = qV/d
|F| = (4.7 x 10⁻⁹ x 3 x 10⁶) / (3.1)
|F| = 4.548 x 10⁻³ N
F = - 4.548 x 10⁻³ N
The net horizontal force experienced by this ball is;
![F_{net} = F_c - mg\\\\F_{net} = -4.548 *10^{-3} - (1.1*10^{-3} * 9.8)\\\\F_{net} = -15.328*10^{-3} \ N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20F_c%20-%20mg%5C%5C%5C%5CF_%7Bnet%7D%20%3D%20-4.548%20%2A10%5E%7B-3%7D%20-%20%281.1%2A10%5E%7B-3%7D%20%2A%209.8%29%5C%5C%5C%5CF_%7Bnet%7D%20%3D%20-15.328%2A10%5E%7B-3%7D%20%5C%20N)
The work done between the ends of the plate is equal to product of the magnitude of net force on the ball and the distance traveled by the ball.
![W = F_{net} *h\\\\W = 15.328 *10^{-3} * h](https://tex.z-dn.net/?f=W%20%3D%20F_%7Bnet%7D%20%2Ah%5C%5C%5C%5CW%20%3D%2015.328%20%2A10%5E%7B-3%7D%20%2A%20%20h)
W = K.E
![15.328*10^{-3} *h = \frac{1}{2}mv^2\\\\ 15.328*10^{-3} *h = \frac{1}{2}(1.1*10^{-3})(4.8)^2\\\\ 15.328*10^{-3} *h =0.0127\\\\h = \frac{0.0127}{15.328*10^{-3}}\\\\ h = 0.827 \ m](https://tex.z-dn.net/?f=15.328%2A10%5E%7B-3%7D%20%2Ah%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5C%2015.328%2A10%5E%7B-3%7D%20%2Ah%20%3D%20%5Cfrac%7B1%7D%7B2%7D%281.1%2A10%5E%7B-3%7D%29%284.8%29%5E2%5C%5C%5C%5C%2015.328%2A10%5E%7B-3%7D%20%2Ah%20%3D0.0127%5C%5C%5C%5Ch%20%3D%20%5Cfrac%7B0.0127%7D%7B15.328%2A10%5E%7B-3%7D%7D%5C%5C%5C%5C%20h%20%3D%200.827%20%5C%20m)
Therefore, the ball traveled 0.827 m