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3 years ago

Please helpppp:////!!!

Mathematics

2 answers:

geniusboy [140]3 years ago

7 0

The answer is C 1,499

Flauer [41]3 years ago

3 0

I believe the answer is C>=1,499.

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What is the y-intercept of the equation of the line that is perpendicular to the line y =

igor_vitrenko [27]

Answer:

y=-5/3x+20

Step-by-step explanation:

Let the equation of the required line be represented as $y=mx+c$

This line is perpendicular to the line $y=\frac{3}{5}x+10$

$=>m*\frac{3}{5}=-1$

$=>m=\frac{-5}{3}$

So the equation of the required line becomes $y=\frac{-5}{3}x+c$

This line passes through the point (15.-5)

$-5=\frac{-5}{3}*15+c$

$=>c=20$

So the equation of the required line is $y=\frac{-5}{3}x+20$

Among the given options, option 4 is the correct one.

3 0

3 years ago

jake rode his bike from 2:30 to 3:30. then he took a shower.he finished his shower 30 minutes after the bike ride ended what tim

Irina-Kira [14]

Answer:

Step-by-step explanation:

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3 years ago

M5-3/2x less than or equal to 1/3

Zepler [3.9K]

Answer: choice A

Step-by-step explanation:

by rearranging the initial inequality you’ll get

$\frac{3}{2} x\leq 5-\frac{1}{3}$

which equals

$\frac{3}{2} x\leq\frac{14}{3}$

then multiply both sides by 2/3

$x\leq \frac{28}{9}$

8 0

3 years ago

Solve for A ? <br><br> Anyone willing to help me :)

GrogVix [38]

Answer:

Step-by-step explanation:

Use the cosine law:

$BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)$

We have:

$BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848$

Substitute:

$a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2$

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3 years ago

What is the volume, in cubic inches, of one cube with an edge length of 1/3 inch

DanielleElmas [232]

Answer:

1/27 cubic in.

Step-by-step explanation:

1/3*1/3*1/3= 1/27

3 0

3 years ago