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docker41 [41]
3 years ago
9

Help with this I can’t come up with anything

Physics
1 answer:
kakasveta [241]3 years ago
3 0
Let’s say you have a spring. You press on the spring with your finger. The spring goes down. This is the action force. Then, the spring goes back up after you take your finger off of it. This is known as the reaction force.
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A man hits a golf ball (0.2 kg) which accelerates at a rate of 20 m/s2. What amount of force acted on the ball?
Delvig [45]
Newton taught us that    Force = (mass) x (acceleration)

Force  =  (0.2) x (20) = <em>4 newtons</em> .

Something to think about:  The ball can only accelerate while the club-face
is in contact with it.  Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.
4 0
3 years ago
A 1000 kg car accelerates from 2.0 m/s to 6.0 m/s in 5.0 s. what is the magnitude of the car's final momentum?
Kazeer [188]
Momentum is computed using below formula.

Momentum = Mass x Velocity, 
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7 0
3 years ago
Review the following observations:
ad-work [718]

Answer:

d.

Explanation:

no explanation

4 0
3 years ago
Read 2 more answers
A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 84 g of water (with an
barxatty [35]
52.1-4.184=47.916 You then either add or subtract this from 68.6 the first temperature of the metal. This will give you your total.
5 0
3 years ago
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QUESTION 2 DOK 3 A Thompson's gazelle has a maximum acceleration of 4.5 m/s2 At this acceleration, how much time is required for
Dominik [7]

Answer:

2.47 s

Explanation:

Convert the final velocity to m/s.

  • 40 km/h → 11.1111 m/s

We have the acceleration of the gazelle, 4.5 m/s².

We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.

We want to find the time t.

Find the constant acceleration equation that contains all four of these variables.

  • v = v₀ + at

Substitute the known values into the equation.

  • 11.1111 = 0 + (4.5)t
  • 11.1111 = 4.5t
  • t = 2.469133333

The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).

5 0
3 years ago
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