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Fudgin [204]
3 years ago
13

An objec with a mass of 7 kg accelerates 5m/s2 when an unknown force is applied to it.what is the magnitude of the unknown force

?
Physics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

<h2>35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7 × 5

We have the final answer as

<h3>35 N</h3>

Hope this helps you

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Hope that helps. 
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3 years ago
A 3.0-kg mass moving in the positive x direction with a speed of 10 m/s collides with a 6.0-kg mass initially at rest. after the
OverLord2011 [107]
Sorry i dont know the answer 
6 0
4 years ago
The law of conservation of mass states that
Jlenok [28]

Hello There!

The law of conservation of mass states that <em>Matter/substances/energy  can not be created or destroyed, it can only be transferred from state to state.</em>

6 0
3 years ago
How high will a 0.345 kg rock go if thrown straight up by someone who does 111 J of work on it? Neglect air resistance.
Eddi Din [679]

To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be

W = PE

W = mgh

Here,

m = mass

g = Acceleration due to gravity

h = Height

our values are,

m = 0.345 kg

g = 9.8m/s^2

W = 111J

Replacing,

W =mgh

111 = (0.345)(9.8)h

h = 32.83m

Then the height is 32.83m.

7 0
3 years ago
A 1-lb block and a 100-lb block are placed side by side at the top of a frictionless hill. Each is given a very light tap to beg
qwelly [4]

Answer:

(c). The two blocks end in a tie

Explanation:

the reason being the absence of any resistance offered to both of the blocks.

if the slope of the hill is for instance 60 deg.

then the acceleration in absence of any resistance is a= 9.81sin(60)

since the acceleration is same then both of the blocks will reach at the same instant

4 0
4 years ago
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