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sweet-ann [11.9K]
1 year ago
7

A nonconducting sphere has mass 80.0 g and radius 20.0cm . A flat, compact coil of wire with five turns is wrapped tightly aroun

d it, with each turn concentric with the sphere. The sphere is placed on an inclined plane that slopes downward to the left (Fig. P29.65), making an angle Ф with the horizontal so that the coil is parallel to the inclined plane. A uniform magnetic field of 0.35T vertically upward exists in the region of the sphere.(b) Show that the result does not depend on the value of Ф .
Physics
1 answer:
seraphim [82]1 year ago
8 0

The torque value is 560 Nm, so the result does not depend on the value of Ф.

Given:

Mass=80.0 g

Radius=20.0 cm

Magnetic field=0.35T

In a magnetic field, a loop of current-carrying wire will experience the following torque:

τ=μ×Β

Here, is the μ magnetic moment and Β is the magnetic field.

τ= 1600 × 0.35 T

τ= 560 Nm

<h3>What is torque and its SI unit?</h3>

The rotating equivalent of force is torque. It is also known as the moment, moment of force, rotating force, or turning effect depending on the field of research. It serves as an example of how a force can alter a body's rotational motion.

The Newton-metre, or kgm2sec-2, is the SI unit for torque. How did we get to this point? Considering the equation Torque = Force X Distance Torque is measured in newton-meters, whereas distance is measured in meters and force is measured in newtons.

To know more about torque , visit :

brainly.com/question/561459

#SPJ4

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What is the net force acting on the buggy. ?The net force is pointing to the ?
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2 years ago
One of your summer lunar space camp activities is to launch a 1130 kg1130 kg rocket from the surface of the Moon. You are a seri
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Answer:

∆U = 2.296×10^10Joules

Explanation:

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Potential energy U = Fr where;

F is the force of attraction between the masses of the moon and the rocket.

r is the radius or height of the object.

From Newton's law of universal gravitation, F = GMm/r²

Potential energy U = (-GMm/r²)×r

Potential energy U = -GMm/r

The force is negative because the objects act upward.

M is the mass of the rocket

m is the mass of the moon

Gravitational potential energy possessed by the rocket

U1 = -GMm/r1

r1 is the altitude covered by the rocket

Gravitational potential energy possessed by the Moon

U2 = -GMm/(r2+r1)

r2 is the radius of the moon

Change in gravitational potential energy ∆U = U2-U1

∆U = -GMm/(r2+r1)-(-GMm/r1)

∆U = -GMm/(r2+r1) + GMm/r1

∆U = -GMm{1/(r2+r1)-1/r1}

Given

G = 6.67×10^-11m³/kgs²

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m = 7.36×10²²kg

r1 = 215km = 215,000m

r2 = 1740km = 1,740,000m

∆U = -6.67×10^-11× 7.36×10²² × 1130{1/(215,000+1,740,000)-1/215000}

∆U= -55.47×10¹⁴{1/1955000-1/215000}

∆U = -55.47×10¹⁴{5.12×10^-7 - 4.65×10^-6}

∆U = -284×10^7 + 257.94×10^8

∆U = 22,954,000,000Joules

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The kinetic energy of an object of mass m and velocity v is given by
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Let's call v_i the initial speed of the car, so that its initial kinetic energy is
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The problem says that the car speeds up until its velocity is twice the original one, so 
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so, if the velocity of the car is doubled, the new kinetic energy is 4 times the initial kinetic energy.
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