I believe the answer would be mass. Low mass stars and medium mass stars often become white dwarfs when they die while high mass stars explode in violent explosions called supernovas and usually leave behind a black hole or a neutron star.
The answer is 4.0075 x 10^9
The circumference of the Earth at the equator is listed as 24,901 miles.
So his speed is
24,901 miles per day.
Convert it to units that we have a better feel for:
(24,901 mi/da) x (1 da / 24 hrs)
= (24,901 / 24) (miles/hour)
= about 1,038 miles per hour.
You'll find a huge number of people on the internet these days,
telling you that you could not be moving at that speed and not
feel it, so therefore the Earth is not spinning, and it's not a globe.
I have a lot of feelings and comments about those people, their
lines of reasoning, and their levels of education and intelligence,
so don't get me started.
I just want to guarantee you that everything you're learning about
the Earth and the solar system in school is well founded, and it's
all based on the life's work of some of the smartest people of the
past 300 years of human history. Everything you're taught about
the Earth has good reasons behind it, whereas those other people
have nothing.
A person on Earth's equator is moving from west to east at roughly
1,038 miles per hour, relative to any point on the Earth's rotation axis.
Answer:
Explanation:
Our values are,
We have all the values to apply the law of linear momentum, however, it is necessary to define the two lines in which the study will be carried out. Being an intersection the vehicle of mass m_1 approaches through the X axis, while the vehicle of mass m_2 approaches by the y axis. In the collision equation on the X axis, we despise the velocity of object 2, since it does not come in this direction.
For the particular case on the Y axis, we do the same with the speed of object 1.
By taking a final velocity as a component, we can obtain the angle between the two by relating the equations through the tangent
Replacing in any of the two functions, given above, we will find the final speed after the collision,
