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Finger [1]
3 years ago
12

ASAP HELP

Chemistry
2 answers:
jeyben [28]3 years ago
7 0

Answer:

the answer is 2.75 but since that isn't an option I'd go with 1 because I just took a test with this question and it was the right answer.. hopefully that helps

BabaBlast [244]3 years ago
6 0

Answer:

2.75

Explanation:

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If the products of a reaction are Co2 and 2H20, what is known about the<br>reactants?​
Svetradugi [14.3K]

Answer:

Reactant : A combustion of hydrocarbon.

Explanation:

It is known that when hydrocarbons are involved in combustion, they produce carbon dioxide and water.

CxHy + (x+y/4)O2 ===> xCO2 + y/2H2O

4 0
3 years ago
How does the rock cycle and plate tectonics interfere with geochemists trying to determine the age of the Earth? Chose the best
Phoenix [80]

Answer:

The rock cycle and plate tectonics cause Earth's rocks to break down over time and they are recycled through natural processes.

Explanation:

Rock cycle(Attachment-1)

4 0
3 years ago
The energy level where an electron is located, is shown by the ______ on the periodic table
Norma-Jean [14]

Answer:

the first energy level is closest to nuclear the second energy level is a little farther away than the first

8 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
3 years ago
Type of reaction in NaOH + KNO3 → NaNO3 + KOH
Lesechka [4]

Answer:

It is a combustion reaction

Explanation:

6 0
3 years ago
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