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2 years ago

What is the atomic mass for this element?0,-3,6,3

Chemistry

2 answers:

labwork [276]2 years ago

8 0

Answer:

Atomic mass = number of protons + number of neurons

Atomic mass = 3+3=6

Explanation:

Note atomic mass is equal to mass number

Sedaia [141]2 years ago

6 0

Answer:

Explanation:

Atomic number refers to the number of protons in the nucleus of the atom.

and since there are 3 protons, the atomic number is 3

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(2pts) During the Purification of Lactate Dehydrogenase (LDH) experiment, you will need 50ml of buffer A150. Buffer A150 is 30mM

torisob [31]

Answer:

The answer is " $20 \ mL$ "

Explanation:

Given:

Molarity= number of moles

because it is 1 Liter

$\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\ Tris\\\\$

therefore,

it takes 20 mL of Tris.

$\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\$

$= 30 \ mL \ of\ Nacl$

So, take $20 \ mL\ of\ NaCl.$

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3 years ago

The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti

maksim [4K]

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>

Half-life (t½) = 4 days
Time (t) = 4 weeks = 4 × 7 = 28 days
Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>

Original amount (N₀) = 100 g
Number of half-lives (n) = 7
Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>

Original amount (N₀) = 100 g
Amount remaining (N)= 0.78125 g

Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

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2 years ago

Balance the nuclear reaction equation for the beta minus decay of nickel-63 by completing the missing numbers.

Marta_Voda [28]

Answer: 63 & 29

Explanation:

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2 years ago

What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?

lana [24]

Answer:

The concentration of the solution is 5.8168 × $10^{-4}$ mol. $dm^{-3}$

Explanation:

Here, we want to calculate the concentration of the solution.

The unit of this is mol/dm^3

So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3

The number of moles = mass/molar mass

molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol

Number of moles = 33.4/87 = 0.384 moles

This 0.384 moles is present in 660 L

x moles will be present in 1 dm^3

Recall 1 dm^3 = 1L

x * 660 = 0.384 * 1

x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3

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2 years ago

If I had 50 graham cracker squares, 15 marshmallows, and 100 little

anastassius [24]

The answer the the question is 22

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2 years ago