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3 years ago

Chemistry neeeeeeed help!

Chemistry

1 answer:

ryzh [129]3 years ago

8 0

<h3> <u>ANSWER</u> </h3>

4. O²-

<h3><u>EXPLANATION</u> </h3>

O²- has 16 electrons while Ne has 18 electrons. O²- is a molecule that has one electron added to each atom, meaning that there are two extra electrons which makes O²- the same electron configuration as of Ne atom.

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The rotational period of the moon is_____

Ivahew [28]

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Hi, I think the D since the moon rotates about once a month and these months have different amounts of days. an example would be February that can have like 28 or 29 in leap year

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3 years ago

The reaction type represented by AB ---> A + B is known as

nordsb [41]

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A. synthesis

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3 years ago

If the gas in the piston above has a volume of 20.0 L at a temperature of 25 degrees C, what is the volume of that gas when it i

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15.98 L

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3 years ago

Read 2 more answers

When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.

Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

$Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3$

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

$0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2$

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

$0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2$

And the resulting percent yield:

$Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%$

Regards!

4 0

3 years ago

How many megagrams are in 90.532 g?

Fed [463]

9.0532e-5 should be correct! hope this helps

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3 years ago