Hello,
<span>3. The parents’ phenotypes are expressed equally in the offspring’s phenotype.</span>
Answer:
M of HI = 5.4 M.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
<em>(XMV) acid = (XMV) base.</em>
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HI = (XMV) Ca(OH)₂.</em>
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>
Answer:
Filtering <span>is best laboratory technique to separate a solid from a liquid to recover the liquid.
Explanation:
A solid particles present in liquids can be separated from liquid by utilizing a membrane having pores large enough to allow the liquid molecules to pass through and small enough to stop the solid particles from crossing.
Example:
Tea Filters are used to separate Tea from the grounds.
Kidney is an excellent example of Biological Filter.
</span><span>Whatman Cellulose Filter Paper used in Chemistry Labs.</span>
Answer:
14 mol O₂
Explanation:
The reaction between CO and O₂ is the following:
CO + O₂ → CO₂
We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:
2CO + O₂ → 2CO₂
As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:
28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂
Answer:
V2= 0.0796m3
Explanation:
We have that for a real gas the following relation is fulfilled:
PV / T = constant
To use this formula I need to pass the pressure of mmHg to KPa and the volume of L to m3, knowing that
1Kpa = 7.50062mmHg
1L = 0.001m3
So i can say
P1V1/T1 =P2V2/T2
So
V2= P1V1T2/P2T1
V2= 51.60KPa*0.034m3*350k/36.53KPa*211k
finally
V2= 0.0796m3