1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tpy6a [65]
3 years ago
15

How many Joules of energy in 3565 calories?

Chemistry
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer: 14915960J

Explanation: I used a calculator converter.

You might be interested in
Mr. Smith wanted to see if the color of light shined on a plant had an effect on the number of leaves it had. He gathered a 2
iragen [17]
Higgffggvtgrjtbrb verve even
3 0
3 years ago
I have no idea what to do please help me quickly!
Irina18 [472]

Answer:

The farther away the planet the slower the revolution around the earth. the closer the faster.

Explanation:

its like a tetherball pole when it wraps around it gets closer and spins faster and faster untill it stops. Brainliest?

6 0
3 years ago
Read 2 more answers
Find the empirical formula of a compound containing: 19.32% Ca, 34.30% Cl, and 46.38% O
Bess [88]
40×19.32/100=7.7=8×2=16Ca
35.5×34.30/100=12.1=12×2=24Cl
16×46.38/100=7.4=7×2=14O
5 0
3 years ago
The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor p
saul85 [17]

Answer : The vapor pressure of bromine at 10.0^oC is 0.1448 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of bromine at 10.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 10.0^oC=273+10.0=283.0K

T_2 = normal boiling point of bromine = 58.8^oC=273+58.8=331.8K

\Delta H_{vap} = heat of vaporization = 30.91 kJ/mole = 30910 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{30910J/mole}{8.314J/K.mole}\times (\frac{1}{283.0K}-\frac{1}{331.8K})

P_1=0.1448atm

Hence, the vapor pressure of bromine at 10.0^oC is 0.1448 atm.

4 0
3 years ago
What does the ideal gas law describe
soldier1979 [14.2K]

the law that the product of the pressure and the volume of one gram molecule of an ideal gas is equal to the product of the absolute temperature of the gas and the universal gas constant.

5 0
4 years ago
Read 2 more answers
Other questions:
  • Is the entropy change favorable or not, when a nonpolar molecule is transferred from water to a nonpolar solvent?
    8·1 answer
  • When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen,
    7·2 answers
  • What is the Lewis structure for NbBr5
    14·1 answer
  • Which of the following musical instruments has the least interia
    5·1 answer
  • "Bromos" Means stench in greek, this is stinky element.
    5·1 answer
  • A strong compact cuticle makes for
    6·1 answer
  • Write electronic configuration of chlorine in its ionic state?​
    5·1 answer
  • Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many mi
    8·1 answer
  • Help please thank you!
    9·1 answer
  • Which of the following practices below are used to help conserve soil?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!