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nataly862011 [7]
3 years ago
9

How many grams are equal to 0.11 mole of copper(I) chromate?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
8 0

Mass of Copper(I) chromate( CuCrO₄) = 19.75 g

<h3>Further explanation </h3>

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

\tt \large{\boxed{\bold{mol=\dfrac{m(mass)}{MW(molecular~weight)}}}

0.11 mole of Copper(I) chromate( CuCrO₄) ⇒ MW=179.54 g/mol, so mass :

\tt mass=mol\times MW\\\\mass=0.11\times 179.54\\\\mass=19.75~g

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There are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus (option A).

<h3>How to calculate number of atoms?</h3>

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number. That is;

no of atoms = no of moles × 6.02 × 10²³

According to this question, there are 30.974 grams of phosphorus in one mole of phosphorus. The number of atoms can be calculated as follows:

no of moles of P = 30.974g ÷ 31g/mol = 0.99mol

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Therefore, there are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus.

Learn more about number of atoms at: brainly.com/question/8834373

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