How many grams are equal to 0.11 mole of copper(I) chromate?

Chemistry

1 answer:

Evgesh-ka [11]3 years ago

8 0

Mass of Copper(I) chromate( CuCrO₄) = 19.75 g

<h3>Further explanation </h3>

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

$\tt \large{\boxed{\bold{mol=\dfrac{m(mass)}{MW(molecular~weight)}}}$

0.11 mole of Copper(I) chromate( CuCrO₄) ⇒ MW=179.54 g/mol, so mass :

$\tt mass=mol\times MW\\\\mass=0.11\times 179.54\\\\mass=19.75~g$

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