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2 years ago

How many grams are equal to 0.11 mole of copper(I) chromate?

Chemistry

1 answer:

Evgesh-ka [11]2 years ago

8 0

Mass of Copper(I) chromate( CuCrO₄) = 19.75 g

<h3>Further explanation </h3>

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

$\tt \large{\boxed{\bold{mol=\dfrac{m(mass)}{MW(molecular~weight)}}}$

0.11 mole of Copper(I) chromate( CuCrO₄) ⇒ MW=179.54 g/mol, so mass :

$\tt mass=mol\times MW\\\\mass=0.11\times 179.54\\\\mass=19.75~g$

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2 years ago

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Answer: I found this online. Hope it helps you.

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3 years ago

How many moles of copper are in 1.51 x 1024 Cu atoms?

kkurt [141]

<h3>Answer:</h3>

2.51 mol Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.51 × 10²⁴ atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})$
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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.50747 mol Cu ≈ 2.51 mol Cu

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