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3 years ago

Write this in a word and skeleton equation:

Chemistry

1 answer:

DiKsa [7]3 years ago

6 0

Answer:

Write this in a word and skeleton equation:

Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.

Explanation:

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At a certain temperature, 0.3411 0.3411 mol of N 2 N2 and 1.661 1.661 mol of H 2 H2 are placed in a 2.50 2.50 L container. N 2 (

Sveta_85 [38]

Answer: The equilibrium constant for the above reaction is 1.31

Explanation:

We are given:

Initial moles of nitrogen gas = 0.3411 moles

Initial moles of hydrogen gas = 1.661 moles

Equilibrium moles of nitrogen gas = 0.2001 moles

For the given chemical reaction:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

Initial: 0.3411 1.661

At eqllm: 0.3411-x 1.661-3x 2x

Evaluating for 'x', we get:

$\Rightarrow (0.3411-x)=0.2001\\\\\Rightarrow x=0.3411-0.2001=0.141$

Volume of the container = 2.50 L

The expression of $K_c$ for the above equation follows:

$K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

We are given:

$[NH_3]=\frac{2\times 0.141}{2.50}=0.1128M$

$[N_2]=\frac{0.2001}{2.5}=0.08004M$

$[H_2]=\frac{1.661-(3\times 0.141)}{2.5}=0.4952M$

Putting values in above expression, we get:

$K_c=\frac{(0.1128)^2}{0.08004\times (0.4952)^3}\\\\K_c=1.31$

Hence, the equilibrium constant for the above reaction is 1.31

5 0

3 years ago

How do i confess to my crush of the same gender? Pls hurry

harkovskaia [24]

Answer:

BE DIRECT, DON'T BE AFRAID. THE FACT THAT THEY ARE OF THE SAME SEX IS NOT RELEVANT.

SPEAK FROM THE HEART, EXPRESS YOUR FEELINGS HONESTLY.... AND IF HE REJECTS YOU, SMILE AND THINK "AT LEAST I TRIED, SOMEONE BETTER WILL EXIST" AND DON'T LET YOURSELF BE PUT DOWN UWU

Explanation:

(SORRY IF IT'S NOT VERY UNDERSTANDABLE, I SPEAK SPANISH AND I'M USING TRANSLATOR ._.)

5 0

3 years ago

Read 2 more answers

How many grams of NaCl are required to make 150.0mL of a 5.000 m solution

Yanka [14]

The number of grams of NaCl required to make 150.0 ml of a 5.000m solution is 43.875 grams

calculation

Step 1: calculate moles of NaCl

moles= molarity x volume in liters

volume in liters = 150.0 ml/1000= 0.15 l