The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1.
Step-by-step explanation:
The given is,
......................................(1)
....................................(2)
Step:1
By elimination method,
Subtracting Equations (1) and (2),


( - )
(
) + (
) = (
)
= 6
= 1
Step:2
Substitute the value of y in equation (1),

+ ( 3 × 1 ) = 5
= 5-3
= 2
Step:3
Check for Solution,
Substitute the values of x and y in Eqn (1),

2 + ( 3 × 1 ) = 5
5 = 5
Result:
The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.
In the point (x, y), if x=0, then the point is on the y axis.
If y=0, the point is on the x axis
If both x and y are positive (greater than 0), the point is in quadrant 1
If x is negative (less than 0) and y is positive (greater than 0), the point is in quadrant 2
If both x and y are negative, the point is in quadrant 3
If x is positive and y is negative, the point is in quadrant 4
Taking (-3, 2), since 3 has a - sign before it (and nothing else), it is negative. Since the x value comes first, this means that x is negative. Since it simply states "2" for the y value, it is positive. As x is negative and y is positive, we know that the point is in quadrant 2.
I challenge you to do this on your own - good luck, and feel free to ask with further questions!
6 * (4 in)^2 = 96 in^2 . . . . area of a 4 inch cube.
Im pretty sure what u put is correct :)
Answer:
I assume you want an equality: -5/9 >= 5x, -1/9>=x