Answer:
An enterprise that produces goods or provides services, usually to make a profit.
Explanation:
Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa
The designers suggest that speech recognition allows for spoken interaction or conversation and spoken prompts or commands.
Explanation:
The speech recognition is used when the user has physical impairments and hands are busy, eyes are occupied and the user cannot read.
We can save time with the usage of speech recognition system. The users are knowledgeable based on the actions available.
The problems faced in speech recognition system are in the noisy environment it has bad microphones and the commands should be learned and remembered.
The other obstacle is error correction is time consuming. the speech production has slow space to speech output provides privacy in public spaces. The disadvantage is it contains large amount of information.
Answer: The United States must lead the space race to prevent future wars.
Explanation: Hope this helps
Answer:
import java.util.*;
public class PerfectNum{
public static String isPerfect(long number){
String s = "";
long sum = 0;
//Checking if the number is perfect or not
for(long i = 1; i < number; i++){
if(number % i == 0){
sum += i;
}
}
if(sum == number){
for(long i = 1; i < number; i++){
String t = "";
if(number % i == 0){
long n = i;
//Converting into string
while(n > 0){
long p = n % 10;
t += (char)(p + '0');
n /= 10;
}
//Reversing the number
for(int j = t.length() - 1; j >= 0; j--){
s += t.charAt(j);
}
s += " ";
}
}
}
return s;
}
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
System.out.println("Enter maximum number");
long n = sc.nextLong();
System.out.println("Displaying perfect numbers 2 to " + n);
for(long i = 2; i <= n; i++){
String s = isPerfect(i);
if(s != "")
System.out.println(s +"->" + i);
}
}
}