**Answer:**

to plan, design, and oversee the construction of a building

**Answer:**

1.0MG

**Explanation:**

to solve this problem we use this formula

S₀-S/t = ksx --- (1)

the values have been given as

concentration = S₀ = 250mg

effluent concentration = S= 10mg

value of K = 0.04L/day

x = 3000 mg

when we put these values into this equation,

250-10/t = 0.04x10x3000

240/t = 1200

we cross multiply from this stage

240 = 1200t

t = 240/1200

t = 0.2

remember the question says that 5MGD is required to be treated

so the volume would be

v = 0.2x5

= **1.0 MG**

**Answer:**

**correct option is (A) 0.5 **

**Explanation:**

**given data **

axial column load = 250 kN per meter

footing placed = 0.5 m

cohesion = 25 kPa

internal friction angle = 5°

**solution**

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for a pure cohesive soil

= 0

and we know formula for is

= (Nq - 1 ) × tan(Ф) ..................1

so here Ф is very less should be nearest to zero

and its value can be 0.5

**so correct option is (A) 0.5 **

**Answer:**

E = 2940 J

**Explanation:**

It is given that,

Mass, m = 12 kg

Position at which the object is placed, h = 25 m

We need to find the potential energy of the mass. It is given by the formula as follows :

E = mgh

g is acceleration due to gravity

So, the potential energy of the mass is 2940 J.

**Express it in standard form and apply the basic indices laws to simplify **