Presentation, or speech I’d imagine
Answer:
The correct answer is "
".
Explanation:
Given:
Maximum load,
P = 50,000 N
Crack length,
a = 3mm
or,
= 3×10⁻³ m
Diameter,
d = 32 mm
As we know,
⇒ Maximum stress, 


Now,
⇒ Fracture tougness, 
On substituting the values, we get


The temperature at which the diffusion coefficient have a value of 2.1×10-5 m 2 /s is -47078 K.
Using the relation;
logD = logDo - Ea/2.303RT
D = diffusion coefficient
Do = preexponential
Ea = activation energy
R = gas constant
T = temperature
Substituting values;
log(2.1×10-5)= log (1.1×10-5 ) - 253,300/2.303 × 8.314 × T
log(2.1×10-5) - log (1.1×10-5 ) = - 253,300/2.303 × 8.314 × T
log[2.1×10-5/1.1×10-5] = - 253,300/2.303 × 8.314 × T
0.281 × (2.303 × 8.314 × T) = - 253,300
T = - 253,300/2.303 × 0.281 × 8.314
T = -47078 K
Learn more: brainly.com/question/14283892
Resisitivty = RA/L = 7*10^-8 ohm meters
Conductivity is the inverse= 14.3*10^6 S/m