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Alenkasestr [34]
3 years ago
13

A light bar AD is suspended from a cable BE and supports a 20-kg block at C. The ends A and D of the bar are in contact with fri

ctionless vertical walls. Determine the tension in cable BE and the reactions at A and D.

Engineering
1 answer:
babymother [125]3 years ago
7 0

Answer:

Tension in cable BE= 196.2 N

Reactions A and D both are  73.575 N

Explanation:

The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence

T_{BE}-W=0 hence

T_{BE}=W=20*9.81=196.2 N

Therefore, tension in the cable, T_{BE}=196.2 N

Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then

196.2\times 0.125- 196.2\times 0.2+ D_x\times 0.2=0

24.525-39.24+0.2D_x=0

D_x=73.575 N

Similarly,

A_x-D_y=0

A_x=73.575 N

Therefore, both reactions at A and D are 73.575 N

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In this lab, your task is to configure the external vEthernet network adapter with the following IPv6 address: Prefix: 2620:14F0
OverLord2011 [107]

Here is the complete question

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You have installed Windows Server 2016 on CorpRTR, which you plan to use to isolate the test segment from the rest of the network. You'll use traditional routing or NAT.

In this lab, your task is to add the necessary role and role services to meet the stated requirements. Do not add unnecessary role services.

Answer & Explanation:

Complete this lab as follows:

1.In the notification area, right-click the Network icon and select Open Network and Sharing Center.

2.On the left, select Change adapter settings.

3.Right-click the vEthernet (External)adapter and select Properties.

4.Select Internet Protocol Version 6 (TCP/IPv6).

5.Select Properties.

6.Select Use the following IPv6 address.

7.In the IPv6 address field, enter 2620:14F0:45EA:0001:192:168:0:10as the IPv6 address.

8.In the Subnet prefix length field, enter 64.

9.Click OK.

10.Click Close.

11.In the Search the web and Windows field, enter cmd.

12.Under Best match, right-click Command Prompt and select Run as Administrator.

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4 0
3 years ago
100000000000x1000000000000=?
zhannawk [14.2K]

Answer:

Thy answer to your very sophisticated question is 1E23

Explanation:

IT JUST IS! Dont ask any questions

mAsquErade, mAsquerade tHat iS mY naME

7 0
2 years ago
Read 2 more answers
Why dose bob not let humans touch him one and only Ivan
gogolik [260]
Sorry man i don’t know sorry
8 0
2 years ago
Is it possible to interface an IC with a different technology such as TTL to HCS12 ports? What are the conditions in terms of el
damaskus [11]

Answer:

The condition is true  when their voltage and current specifications with their impedance are matched or complementary to each other.

Explanation:

Solution

Yes it is possible or true to interface an IC with a different technology like the TTL to HCS12 ports. but the condition is that their current and voltage specifications should be matched and their impedance and power also should be matched.

What this implies is that both their voltage and current requirements should be complementary to each other so as their impedance.

6 0
3 years ago
A hypothetical metal alloy has a grain diameter of 2.4 × 10−2 mm. After a heat treatment at 575°C for 500 min, the grain diamete
Alex

Answer:

The time required is 10.078 hours or 605 min

Explanation:

The formula to apply here is ;

K=(d²-d²₀ )/t

where t is time in hours

d is grain diameter to be achieved after heating in mm

d₀ is the grain diameter before heating in mm

Given

d=5.5 × 10^-2 mm

d₀=2.4 × 10^-2 mm

t₁= 500 min = 500/60 =25/3 hrs

t₂=?

n=2.2

First find K

K=(d²-d²₀ )/t₁

K={ (5.1 × 10^-2 mm)²-(2.4 × 10−2 mm)² }/ 25/3

K=(0.051²-0.024²) ÷25/2

K=0.000243 mm²/h

Re-arrange equation for K ,to get the equation for d as;

d=√(d₀²+ Kt)  where now t=t₂

d=\sqrt{0.024^2+0.000243*t} \\\\0.055=\sqrt{0.024^2+0.000243t} \\\\0.055^2=0.024^2+0.000243t\\\\0.055^2-0.024^2=0.000243t\\\\0.002449=0.000243t\\\\0.002449/0.000243=t\\\\10.078=t\\\\t=605min

4 0
3 years ago
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