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lesya692 [45]
2 years ago
7

The diameter of a circle is 4cm. Which equation can be used to find its circumference? A. C=pi x2 B. C=pi x 4 C. C=pi x 4/2 D. C

= pi x 4/4
Mathematics
1 answer:
rodikova [14]2 years ago
8 0

Answer:

d is correct

Step-by-step explanation:

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Answer:

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The steepness of a line expressed as a ratio, using any two points on the line.

y-intercept

The value of  y  at the point where a curve crosses the y-axis.

Step-by-step explanation:

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Are the graphs of each pair of equations parallel, perpendicular,or neither? PLEASE I NEED YOUR HELP
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Answer:

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7 0
3 years ago
in 2018 GRE scores were normally distributed with a mean of 303, and standard deviation of 13. Standford University Graduate sch
eduard

Answer:

The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 303, \sigma = 13

What is the minimum score needed to be considered for admission to Stanfords graduate school?

Top 2.5%.

So X when Z has a pvalue of 1-0.025 = 0.975. So X when Z = 1.96

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 303}{13}

X - 303 = 13*1.96

X = 328.48

The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.

3 0
3 years ago
does anyone know how to solve this? i dont remember doing any problems in class related to this and this single question alone h
Serggg [28]

Answer:

The answer to your question is below

Step-by-step explanation:

Process

1.- Get two points of each line to find the equation of each line

   Continuous line    A (-10, 0)  B (0, 9)

   Dotted line            C (-2, -3)   D (0, -10)

 Slope continuous line    m = \frac{9 - 0}{0 + 10} = = \frac{9}{10}

 Slope dotted line     m = \frac{-10 + 3}{0 + 2} = \frac{-7}{2}

2.- Get the equation of each line

     Continuous line    y + 0 = 9/10 (x + 10)

                                   y = 9/10x + 9

      Dotted line          y + 3 = -7/2(x + 2)

                                    y + 3 = -7/2x - 7

                                    y = -7/2x -7 - 3

                                    y = -7/2x - 10

3.- Find the inequalities

   <u> Continuous line</u> (we need the upper area of the line, we use ≥)

                               y ≥ 9/10x + 9

   The <u>Dotted line</u> (we also need the upper area, we use >)

                              y > -7/2x - 10

6 0
3 years ago
Read 2 more answers
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