Question

Please help will mark brainliest!!

Answer 1

Answer:

find the area for the triangles then find the area of the rectangles and add them together  and u have your answer do the same for both questions

Step-by-step explanation:

Answer 2

Answer:

9 - 166.42m²

10 - 308.8cm²

Step-by-step explanation:

The first figure shown is a triangular prism

We can find the surface area using this formula

$SA=bh+L(S_1+S_2+h)$

where

B = base length

H = height

L = length

S1 = base length

S2 = slant height ( base's hypotenuse )

The triangular prism has the following dimensions

Base Length = 4m

Height = 5.7m

Length = 8.6m

S1 = 4m

S2 = 7m

Having found the needed dimensions we plug them into the formula

SA = ( 4 * 5.7 ) + 8.6 ( 4 + 7 + 5.7 )

4 * 5.7 = 22.8

4 + 7 + 5.7 = 16.7

8.6 * 16.7 = 143.62

22.8 + 143.62 = 166.42

Hence the surface area of the triangular prism is 166.42m²

The second figure shown is a pyramid

The surface area of a pyramid can be found using this formula

$SA = A+\frac{1}{2} ps$

Where

A = Area of base

p = perimeter of base

s = slant height

The base of the pyramid is a square so we can easily find the area of the base by multiplying the base length by itself

So A = 8 * 8

8 * 8 = 64

So the area of the base (A) is equal to 64 cm^2

The perimeter of the base can easily be found by multiplying the base length by 4

So p = 4 * 8

4 * 8 = 32 so p = 32

The slant height is already given (15.3 cm)

Now that we have found everything needed we plug in the values into the formula

SA = 64 + 1/2 32 * 15.3

1/2 * 32 = 16

16 * 15.3 = 244.8

244.8 + 64 = 308.8

Hence the surface area of the pyramid is 308.8cm²