Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Answer:
3.74 atmospheres
Explanation:
If the temperature is constant, then the formula is
V*P = V1 * P1
V = 22.6 L
P = 1.67 atm
V1 = 10.0 L
P1 = ??
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22.6 * 1.67 = 10 * P1
37.742 = 10 * P1
37.742/10 = P1
P1 = 3.742
Note there are 3 sig digs in each given, so the answer should be
P1 = 3.74 atmospheres
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