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lesya [120]
3 years ago
12

Explain in detail what happens when an acid and a base mix. Try to use the words ions, attraction, neutral and bonding in your a

nswer.
( I understand how to use all keywords except from attraction, when does attraction occur in neutralization?)
Chemistry
1 answer:
Anton [14]3 years ago
5 0

Answer:

when acid and the base mix it is bonding together and that makes it have a little blast but because of the acid

Explanation:

acid is the mane thing that makes 50% of things blast like as if i were to put baking soada and acid it would blast.  

Click the heart if this was helpful

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What is molecular formula of Ozone?​
zmey [24]

Answer:

the molecular formula of Ozone is O_3.

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3 years ago
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How much energy does an X-ray with an 8 nm (8 x 10-9m) wavelength have?
myrzilka [38]

Answer:

it would be option C

Explanation:

Speed of light = 3×10^8m/s

Planck's constant = 6.626×10^-34 Js

Wavelength = 8 x 10^-9 m

Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9

Energy = [19.878×10^(8-34)] / 8 x 10^-9

Energy = 2.48475 × 10^(-26+9)

Energy = 2.48×10^-17 J

3 0
3 years ago
What is the pH of a 0.75 M HNO3 solution
Sauron [17]
Hello!

The dissociation reaction of HNO₃ is the following:

HNO₃ → H⁺ + NO₃⁻

This is a strong acid, so the concentration of HNO₃ would be the same as the concentration of H⁺. The formula for pH is the following:

pH=-log([H_3O^{+}])=-log(0,75M)=0,12

So, the pH would be 0,12

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4 0
3 years ago
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Identify the hybridization of the c atom in ch2br2.
Oliga [24]
Hello!

The hybridization of the C atom in CH₂Br₂ is sp3

When bonding, the orbitals "s" and "p" from C atoms interact to form hybridized orbitals. If the C atom has 4 sigma bonds, as is the case in CH₂Br₂, there are 4 hybridized orbitals required, so 1 "s" orbital and 3 "p" orbitals hybridize to form an sp3 hybrid orbital. This orbital has tetrahedral geometry and the bond angle is 109,5 °.

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7 0
3 years ago
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The buffer solution is used to control the pH to insure that it does not become too high because excessively basic solutions cou
oksian1 [2.3K]

Answer:

pH = 12.7

Explanation:

First, we have to calculate the [Ca²⁺] in a solution of about 250 ppm CaCO₃.

\frac{250mgCaCO_{3}}{L} .\frac{1gCaCO_{3}}{1000mgCaCO_{3}} .\frac{1molCa^{2+} }{100gCaCO_{3}} =2.5 \times 10^{-3} M

Now, let's consider the dissolution of Ca(OH)₂ in water.

Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

The solubility product Ksp is:

Ksp = [Ca²⁺] × [OH⁻]²

[OH⁻] = √(Ksp/[Ca²⁺]) = √(6.5 × 10⁻⁶/2.5 × 10⁻³) = 5.1 × 10⁻² M

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (5.1 × 10⁻²) = 1.3

pH + pOH = 14 ⇒ pH = 14 - pOH = 14 - 1.3 = 12.7

5 0
3 years ago
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