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lesya [120]
3 years ago
12

Explain in detail what happens when an acid and a base mix. Try to use the words ions, attraction, neutral and bonding in your a

nswer.
( I understand how to use all keywords except from attraction, when does attraction occur in neutralization?)
Chemistry
1 answer:
Anton [14]3 years ago
5 0

Answer:

when acid and the base mix it is bonding together and that makes it have a little blast but because of the acid

Explanation:

acid is the mane thing that makes 50% of things blast like as if i were to put baking soada and acid it would blast.  

Click the heart if this was helpful

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Give three examples,from the lab where potential energy was converted to kinetic energy?​
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Answer:

*a car geared neutral that is at a stop. two men start pushing it

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Explanation:

everthing has to be at a complete stop then through energy be moved

7 0
3 years ago
What is a solute?
olya-2409 [2.1K]

Answer:

C. The substance that is dissolved in another substance

Explanation:

a solute is a substance dissolved in another substance, known as a solvent

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2 years ago
What is the volume of a box measuring 2cm by 3cm by 4cm?
grin007 [14]

I The answer is 42 cubic cm

3 0
2 years ago
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At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?
Nadya [2.5K]

Answer:

V = 57.39 L

Explanation:

Given that,

Temperature, T = 300 K

Pressure, P = 0.987 atm

No. of moles of Ne, n = 2.30 mol

We need to find the volume of Ne. We know that, the ideal gas law is as follows :

PV = nRT

Where

P is pressure and R is gas constant

V=\dfrac{nRT}{P}\\\\V=\dfrac{2.3\times 0.0821\times 300}{0.987 }\\\\V=57.39\ L

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3 0
3 years ago
The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab
mixas84 [53]

Answer:

See the answers below

Explanation:

1)  100. mL of solution containing 19.5 g of NaCl  (3.3M)

2)  100. mL of 3.00 M NaCl solution (3 M)

3) 150. mL of solution containing 19.5 g of NaCl  (2.2 M)

4)  Number 1 and 5 have the same concentration (1.5M)

MW of NaCl = 23 + 36 = 59 g

For number 3

          59 g ------------------- 1 mol

           19,5 g -----------------   x

  x = 19.5 x 1/59 = 0.33 mol

Molarity (M) = 0.33 mol/0.150 l = 2.2 M

For number 4,

Molarity (M) = 0.33mol/0.10 l = 3.3 M

For number 5

Molarity (M) = 0.450/0.3 = 1.5 M

4 0
3 years ago
Read 2 more answers
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