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kaheart [24]
2 years ago
11

PH que tendra una solución cuya concentracion de [OH-] = 1x10-4

Chemistry
1 answer:
natta225 [31]2 years ago
7 0
I don’t understand wha u just said but thanks for the points
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I NEED HELP!!!!!!!!!!!!!!!!!!!!!!!
Karolina [17]

Answer:

B.Self powered

Explanation:

They move by themselves.Hope this answer helps you ;)

6 0
3 years ago
How much energy is required to raise the temperature of a 300.0
Montano1993 [528]

Answer:

Q = 1455.12 Joules.

Explanation:

Given the following data;

Mass = 300 grams

Initial temperature = 22.3

Final temperature = 59.9°C

Specific heat capacity = 0.129 J/gºC.

To find the quantity of energy;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt represents the change in temperature.

dt = T2 - T1

dt = 59.9 - 22.3

dt = 37.6°C

Substituting the values into the equation, we have;

Q = 300*0.129*37.6

Q = 1455.12 Joules.

8 0
3 years ago
Which phase of matter is distinguished by a superheated gas that emits light?
mariarad [96]

Answer:

I think it is Plasma

Explanation:

7 0
2 years ago
If 28 grams of N reacts completely with 12 grams of H2, then how many
Bogdan [553]

Answer:

Mass of NH₃ produced = 34 g

Explanation:

Given data:

Mass of nitrogen = 28 g

Mass of Hydrogen = 12 g

Mass of NH₃ produced = ?

Solution:

Chemical equation:

N₂ +  3H₂    →   2NH₃

Moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 28 g/ 28 g/mol

Number of moles = 1 mol

Moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 12 g/ 2 g/mol

Number of moles = 6 mol

Now we will compare the moles of hydrogen and nitrogen with ammonia.

                            H₂              :               NH₃

                            3                :                2

                            6                :             2/3×6 = 4 mol

                           N₂              :                NH₃

                            1                :                 2

Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.

Mass of ammonia produced:

Mass = number of moles × molar mass

Mass =  2 mol  ×  17 g/mol

Mass = 34 g

                     

5 0
3 years ago
Read 2 more answers
20.0 mL of 0.06 M HCl (in a flask) is titrated with 0.04 M NaOH (in a burette). How many milliliters of NaOH needs to be used to
Liula [17]
<span>0.0200 L X 0.06 mol/L HCl = 1.2X10^-3 mol HCl
Moles NaOH added to reach equivalence point = 1.2X10^-3 mol NaOH
Volume NaOH = 1.2X10^-3 mol / 0.0400 M NaOH = 0.030 L NaOH = 30 mL NaOH
</span>
D.There is a rapid change in pH near the equivalence point (pH = 7)
hope it helps
8 0
2 years ago
Read 2 more answers
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