The energy to vaporize the water at its normal boilng point (100°C) is the vaporization latent heat.
The vaporization latent heat of water is 2257 J/ g (you can find it in a textbook, tables or internet).
So, with 955 kJ you can vaporize this amount of water:
[995 kJ * 1000J/kJ ] / 2557 J /g = 389.13 g
Use the density to convert to volume: D = M / V => V = M / D
V = 389.13 g / 1.00 g / ml = 389.13 ml, which rounded to 3 significant figures is 389 ml
Answer: 389 ml
I think u need to be more specific on this question i would help sorry
Oxidation is a process which involves losing electrons in a reaction by an ion, atom or a molecule. It happens when the oxidation state of the ion, atom or the molecule is being increased. Chloride anions has an oxidation state of -1 and dichlorine has an oxidation state of zero or neutral charge. The balanced half-reaction would be written as:
2Cl- = Cl2 + 2e-
To balance the charge on both sides, two electrons should be produced or released by the anion form of chlorine. Being oxidized would mean that the charge of the ion or molecule is being increased. In this case, it is increased from -1 to 0.
Answer:
4.16g of MgCl2
Explanation:
First, let us generate a balanced equation for the reaction:
Mg + 2HCl —> MgCl2 + H2
Molar Mass of Mg = 24g/mol
Molar Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g
From the equation,
24g of Mg produced 95g of MgCl2.
Therefore, 1.05g of Mg will produce = (1.05x95)/24 = 4.16g of MgCl2