Answer:
goodman = 0.694
life of beam = 211597
Explanation:
alternating stress = 48 kpsi
mean stress = 24 kpsi
ultimate strength = 100 kpsi
endurance limit = 40 kpsi
goodman:
= 
= 
= 0.24 + 1.2 = 
N = 1/1.44
N = 0.694
2. check attachment for diagram
Log(N)-3/3 = log90 - log48/log90 - log40
Log(N)-3/3 = 0.77517
Log N = 5.325509
N = 10^(5.325509)
N = 211597
Answer:
Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m
Explanation:
Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.
We know that heat transfer by convection is given by

where,
h = heat transfer coefficient = 10.45
(free convection in air)
A = Surface Area of the pipe
Applying the given values in the above formula we get

Answer:
C
Explanation:
Hydraulic systems can increase or decrease the force applied to them. To make the force larger, the pressure is applied to a larger area. For example, if a 100-N force is applied to the left cylinder in (Figure) and the right cylinder has an area five times greater, then the output force is 500 N.
Answer:
The statement regarding the mass rate of flow is mathematically represented as follows 
Explanation:
A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure
As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.
The above statement can be mathematically written as

this is known as equation of conservation of mass / Equation of continuity.
Now we know that in a time 't' the volume that enter's the Junction 'O' is
1) From pipe 1 = 
1) From pipe 2 = 
Mass leaving the junction 'O' in the same time equals
From pipe 3 = 
From the basic relation of density, volume and mass we have

Using the above relations in our basic equation of continuity we obtain

Thus the mass flow rate equation becomes 
Answer:
The current at t= 0 sec, is 0 A
The current at t= 0.5 sec, is 2.2 A
The current at t= 1 sec, is 4.4 A
Explanation:
Given that
q(t) = 2.2 t²
We know that:- the change in the charge w.r.t. time is known as current. So,

q(t) = 2.2 t²

I= 4.4 t
1.
t = 0 s :
I = 4.4 x 0 = 0 A
<u>Therefore, the current at t= 0 sec, is 0 A</u>
2 .
t= 0.5 s :
I = 4.4 x 0.5 = 2.2 A
<u>Therefore, the current at t= 0.5 sec, is 2.2 A</u>
3.
t= 1 s
I = 4.4 x 1 =4.4 A
<u>Therefore, the current at t= 1 sec, is 4.4 A</u>