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ANTONII [103]
3 years ago
14

Drag each label to the correct location on the chart. Classify the organisms based on how they obtain food.

Engineering
2 answers:
Yuliya22 [10]3 years ago
7 0

Answer: its there

Explanation:

Arisa [49]3 years ago
3 0

Autograph: Trees (Image 1), algae (Image 4), carrots (image 6)

Heterograph: Tiger (Image 2), deer (image 3), human (image 5)

Explanation:

The difference between autotroph and heterotroph organisms is the way they obtain energy. In the case of the first category, these include organisms that can produce energy by a process known as photosynthesis. This covers all plants and similar such as tress, algae, and carrots.

On the other hand, heterotrophic organisms cannot produce energy and need to feed on other organisms, which can include feeding on plants or animals. In this context, this category includes tigers because they feed on other animals, deer because they feed on plants, and humans because we feed on plants and animals.

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I WILL GIVE 20 POINTS!!
Alex777 [14]

Answer:

Use a resume header

Explanation:

Create a Summary

Research industry, employer keywords

there are some hints okay

5 0
3 years ago
Read 2 more answers
Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical
dusya [7]

Answer:

The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm

Explanation:

For steel bolt

Stress = 210 MPa or 210 N/mm2

Pressure = Stress* Area

Pbolt = 210 N/mm2 * 16^2 *(pi)/4

Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6  N

For Brass spacer

Pressure = 42201.6  N

Area of Brass spacer = Pressure/Stress

Area of Brass spacer = 42201.6  N/145 N/mm^2 = 291.044 mm^2

Area of Brass spacer = (pi) (d^2 - 16^2)/4 =  291.044 mm^2

d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758

d^2 =  370.758 + 16^2

d^2 =   626.758

d = 25.03 mm

The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm

5 0
3 years ago
A disk of radius 2.1 cm has a surface charge density of 5.6 µC/m2 on its upper face. What is the magnitude of the electric field
Assoli18 [71]

Answer:

=6.3*10^3 N/C

Explanation:

solution:

from this below equation (1)

E=σ/2εo(1-\frac{z}{\sqrt{z^2-R^2} } )...........(1)

we obtain:

=5.6*10^-6 \frac{c}{m^2} /2(8.85*10^-12\frac{c^2}{N.m^2} ).(1-\frac{9.5 cm}{\sqrt{9.5^2-2.1^2} } )

=6.3*10^3 N/C

8 0
3 years ago
What is one of the “don’ts” in drawing dimension lines? they should never be labeled they should never be stacked they should ne
Strike441 [17]

Answer:

What is one of the “don’ts” in drawing dimension lines? they should never be labeled they should never be stacked they should never cross each other they should never have only one measurement value

5 0
4 years ago
Read 2 more answers
For which situation will structural firefighting protective clothing provide you with adequate protection
jeka94

Missing part

The options are:

A. You will be exposed to splashes of the material.

B. You will have to handle the material.

C. There are high atmospheric concentrations of the material.

D. None of the above.

Answer:

None of the above

Explanation:

Structural firefighting protective clothing can't give adequate protection when one is exposed to splashes of the material. Moreover, it can't help in a situation where one is required to handle the material or when there are high atmospheric concentrations of the material.

SFC may be used when the following conditions are met:

• Contact with splashes of extremely hazardous materials is unlikely.

• Total atmospheric concentrations do not contain high levels of chemicals toxic to the skin.  

• There are no adverse effects from chemical exposure to small areas of unprotected skin.

• Live victims who are in need of rescue, such as those found in a terrorist attack.  

3 0
3 years ago
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