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zalisa [80]
3 years ago
9

The Greek alphabet has 24 distinct lowercase letters. How many bits are needed to be able to encode any single lowercase Greek l

etter
Engineering
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

You need 5 bits to encode al the 24 greek distinct lowercase letters.

Explanation:

o encode 24 greek distinct lowercase letters, you should be able to write in binary language 24 different combinations.

With 1 bit you have only 2 possible combinations. Not enough.

With 2 bit you have only 4 possible combinations. Not enough.

With 3 and 4 bit you have only 8 and 16 possible combinations. Not enough.

With 5 bit you have 32 possible combinations. This is enough to encode all the 24 Greek letters.

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Explain the differences among sand, silt, and clay, both in their physical characteristics and their behavior in relation to bui
3241004551 [841]

Answer:PHYSICALLY- sand is spherical in shape with large particles up to 0.18g

Silt also contains more of spherical particles with weights around 0.0029g.

Clay contain plate like particles,which are flat or layered. It's particles are generally lower that silt and sand below 0.0029g.

BEHAVIORS Sand particles are coarse and very porous,water can easily penetrate with no particles cohesion,does not retain water, difficult to expand,it is IDEAL FOR BUILDINGS.

Silt particles are also porous with some coarseness and no particles cohesion. retains water and can expand. NOT IDEAL FOR BUILDINGS.

Clay contain particles that are not coarse,they have high cohesiveness,they are not porous as it is difficult for water to penetrate. NOT IDEAL FOR BUILDINGS.

Explanation: Sand particles are coarse,very porous,contains spherical particles with large particles sizes and IDEAL FOR BUILDINGS

Silt particles are also porous, with some coarseness and with little or no particles cohesion, NOT IDEAL FOR BUILDINGS.

Clay soils are not porous water can not easily flow thought it,it is hard when dry and soft when wet. IT IS NOT A GOOD OPTION FOR BUILDINGS.

6 0
3 years ago
A man weighs 145 lb on earth.Part ASpecify his mass in slugs.Express your answer to three significant figures and include the ap
adell [148]

Answer:

<em>a) 4.51 lbf-s^2/ft</em>

<em>b) 65.8 kg</em>

<em>c) 645 N</em>

<em>d) 23.8 lb</em>

<em>e) 65.8 kg</em>

<em></em>

Explanation:

Weight of the man on Earth = 145 lb

a) Mass in slug is...

32.174 pound = 1 slug

145 pound = x slug

x = 145/32.174 = <em>4.51 lbf-s^2/ft</em>

b) Mass in kg is...

2.205 pounds = 1 kg

145 pounds = x kg

x = 145/2.205 = <em>65.8 kg</em>

c) Weight in Newton = mg

where

m is mass in kg

g is acceleration due to gravity on Earth = 9.81 m/s^2

Weight in Newton = 65.8 x 9.81 = <em>645 N</em>

d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,

1 m/s^2 = 3.2808 ft/s^2

x m/s^2 = 5.30 ft/s^2

x = 5.30/3.2808 = 1.6155 m/s^2

weight in Newton = mg = 65.8 x 1.6155 = 106

weight in pounds = 106/4.448 = <em>23.8 lb</em>

e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth

mass on the moon = <em>65.8 kg</em>

3 0
3 years ago
Add the following vector given in rectangular form and illustrated the process graphically A = 16+j12, B= 6+j10.4
MariettaO [177]

Answer:

A=16+j12…'B=6+j10.4

Explanation:

add the following vector given in

3 0
1 year ago
Technician A says that if fuel pump pressure is correct, fuel pump volume will be correct as well. Technician B says that a fuel
guajiro [1.7K]

Answer:

Technician B only

Explanation:

hope this helps :)

5 0
2 years ago
How do you solve this. I dont know how so I need steps if you dont mind
galben [10]

Explanation:

all I know is every number that have a bar on is equal to one

4 0
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