Answer:
13.95
Explanation:
Given :
Vector A polar coordinates = ( 7, 70° )
Vector B polar coordinates = ( 4, 130° )
To find A . B we will
A ( r , ∅ ) = ( 7, 70 )
A = rcos∅ + rsin∅
therefore ; A = 2.394i + 6.57j
B ( r , ∅ ) = ( 4, 130° )
B = rcos∅ + rsin∅
therefore ; B = -2.57i + 3.06j
Hence ; A .B
( 2.394 i + 6.57j ) . ( -2.57 + 3.06j ) = 13.95
Answer:Report writing consists of the history and facts of a project or of any kind of event. It is useful to record past history and an overall summary of decisions. Report writing helps to solve problems as a path. Writing a report will guide you in a way that will modernize details of the improvements and upcoming plans.
Answer:
Output signal shape: square, from 0.1 to 230 MHz. Output power: -10 dBm (at a load of 50 Ohms).
Explanation:
I think it’s structural engineers but still check with the others
Answer:
The answer is "2 m/s".
Explanation:
The triangle from of the right angle:
![\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant](https://tex.z-dn.net/?f=%5Cto%20%28x_c-0.8%29%2B%281.5%2By_4%29%20%2B%5Csqrt%7Bx_c%5E2%20%2B%201.5%5E2%7D%3D%20constant)
Differentiating the above equation:
![\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\](https://tex.z-dn.net/?f=%5Cto%20V_c%20%2BV_A%2B%20%5Cfrac%7BX_cV_c%7D%7B%5Csqrt%7Bx_c%5E2%20%2B1%7D%7D%3D0%5C%5C%5C%5C%5Cto%201-V_A%2B%20%5Cfrac%7B0.8%20%5Ctimes%201.5%7D%7B%5Csqrt%7B%200.8%5E2%2B1.5%7D%7D%3D0%5C%5C%5C%5C)
![\to V_A= \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\](https://tex.z-dn.net/?f=%5Cto%20V_A%3D%20%20%5Cfrac%7B1.2%7D%7B%5Csqrt%7B%200.64%2B1.5%7D%7D%2B1%5C%5C%5C%5C)
![= \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1.2%7D%7B%201.46%7D%2B1%5C%5C%5C%5C%3D%20%5Cfrac%7B1.2%2B%201.46%7D%7B%201.46%7D%5C%5C%5C%5C%20%3D%20%5Cfrac%7B2.66%7D%7B1.46%7D%5C%5C%5C%5C%3D%201.82%20%5C%20%5Cfrac%7Bm%7D%7Bs%7D%5C%5C%5C%5C%3D%202%20%5C%20%5Cfrac%7Bm%7D%7Bs%7D)