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Oksi-84 [34.3K]
3 years ago
11

If you are unsure about holding a piece of wood to be drilled, then you should always use a

Engineering
1 answer:
alisha [4.7K]3 years ago
4 0
C I took construction class
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Which option distinguishes the step in the engineering design phase described in the following scenario?
rewona [7]

Answer:

reasearching the problem

Explanation:

EDG

7 0
3 years ago
What does a graphic designer need to do to monitor the progress of the project<br>​
Sholpan [36]

Answer:

At first the graphic designer has to break the process down into it's fundamental components. Which could be:

1) Discussion and Clear Comprehension of the Brief

2) Research and Collection of Information

3) Sketching

4) Execution and Experimentation

5) Finalization

6) Revision and Further Corrections

7) Submissions

Then self-analysis is required to figure out the current stage process. Project management soft-wares such as Trello could be helpful when it comes to tracking the progress. Hope this answers the question.

Explanation:

5 0
3 years ago
A transmission line (TL) of length L and conductance per unit length G' is connected to an ideal constant voltage generator V. T
Andru [333]

Answer:

The Current will decrease by a factor of 2

Explanation:

Given the conditions, it should be noted that the current in the circuit is determined by the LOAD. In other words, the amount of current generator will be producing depends upon the load connected to it.

Now, as the question says, the load is reduced to half its original value, we can write:

P1 = \sqrt{3} (V) (I1) Cos\alpha ----- (1)

P2 = \sqrt{3} (V) (I2) Cos\alpha\\

Since, P2 = P1/2,

P1/2 = \sqrt{3} (V) (I2) Cos\alpha ----- (2)\\

Dividing equations (1) and (2), we get,

P1 / (P1/2) = I1/ I2

I2 = I1 / 2\\

Hence, it is proved that the current in the transmission line will decrease by a factor of 2 when load is reduced to half.

7 0
3 years ago
Race car is accelerating and has a velocity of 10 m/s @ t=0. It completes a lap on a circular track of 400 m in 14 seconds. Calc
wariber [46]

Answer:

component of acceleration are a = 3.37 m/s² and ar = 22.74 m/s²

magnitude of acceleration is  22.98 m/s²

Explanation:

given data

velocity = 10 m/s

initial time to = 0

distance s = 400 m

time t = 14 s

to find out

components and magnitude of acceleration after the car has travelled 200 m

solution

first we find the radius of circular track that is

we know  distance S = 2πR

400 = 2πR

R = 63.66 m

and tangential acceleration is

S = ut + 0.5 ×at²

here u is initial speed and t is time and S is distance

400 = 10 × 14  + 0.5 ×a (14)²

a = 3.37 m/s²

and here tangential acceleration is constant

so  velocity at distance 200 m

v² - u² = 2 a S

v² = 10² + 2 ( 3.37) 200

v = 38.05 m/s

so radial acceleration at distance 200 m

ar = \frac{v^2}{R}

ar = \frac{38.05^2}{63.66}

ar = 22.74 m/s²

so magnitude of total acceleration is

A = \sqrt{a^2 + ar^2}

A = \sqrt{3.37^2 + 22.74^2}

A = 22.98 m/s²

so magnitude of acceleration is  22.98 m/s²

8 0
3 years ago
.. You should
Darya [45]

Answer:

C.

Explanation:

You want to make sure it still works. You don't want to move it periodically though in case of an emergency.

5 0
3 years ago
Read 2 more answers
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