Cone Volume = (PI * radius ^2 * height) / 3
Cone Volume = (PI * 2^2 * 5) /3
Cone Volume = (PI * 20) / 3 <span>
</span><span>Cone Volume = 20.9439510239 cubic inches</span>
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Source:http://www.1728.org/volcone.htm
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Answer:
[μ-error, μ + error]
[14000- 3000, 14000 + 3000]
Step-by-step explanation:
We write it how an interval, where the center of the interval is the mean, thus
[μ-error, μ + error]
First we calculate the mean
μ = (11000+17000)/2
μ = $14000
And the error is the absolute value of the difference between the mean an either extreme values
error = |14000 -17000| = |14000 - 11000| = 3000
Then
[14000- 3000, 14000 + 3000]
The day of the month that was 75% of the pond algae-free is: on day 28 or third day.
<h3>75% of the pond algae-free</h3>
Since we were told the algae doubled every day until it was covered in algae on day 30 of the month.
Hence:
Day 30 (First day)= It was 100% covered.
Day 29 (Second day)=It was 50% covered.
Day 28 (Third day )=it was 25% covered, which will be the same as 75% pond algae-free.
Therefore the day of the month that was 75% of the pond algae-free is: on day 28 or third day.
Learn more about 75% of the pond algae-free here:brainly.com/question/14948447
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The complete question is:
amount of algae covering the Smith's backyard pond doubled every day until it was completely covered in algae on day 30 of the month. On what day of that month was 75% of the pond algae-free?
Answer:
X=45
Step-by-step explanation:
45+3x=180
180-45=135
135/3=45
x has to be 45
x=45
Step-by-step explanation:
Let x represent the first number, and y be the second number.
The first statement can be modeled as
![{x}^{2} - {y}^{2} = 15](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7By%7D%5E%7B2%7D%20%20%3D%2015)
The second statement can modeled as
![2 {x}^{2} - {y}^{2} = 30](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7By%7D%5E%7B2%7D%20%20%3D%2030)
If we multiply 2 both sides of the first equation,
![2( {x}^{2} - {y}^{2} ) = 15 \times 2](https://tex.z-dn.net/?f=2%28%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7By%7D%5E%7B2%7D%20%29%20%3D%2015%20%5Ctimes%202)
![2 {x}^{2} - 2 {y}^{2} = 30](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20-%202%20%7By%7D%5E%7B2%7D%20%20%3D%2030)
Subsitue this for 30 in second equation,
![2 {x}^{2} - {y}^{2} = 2 {x}^{2} - {2y}^{2}](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7By%7D%5E%7B2%7D%20%20%3D%202%20%7Bx%7D%5E%7B2%7D%20%20-%20%20%7B2y%7D%5E%7B2%7D%20)
![{y}^{2} = 0](https://tex.z-dn.net/?f=%20%7By%7D%5E%7B2%7D%20%20%3D%200)
![y = 0](https://tex.z-dn.net/?f=y%20%3D%200)
Subsitue this for y in either equation,
So our answer is
plus or minus sqr root of 15, 0).
![(± \sqrt{15} ,0)](https://tex.z-dn.net/?f=%28%C2%B1%20%5Csqrt%7B15%7D%20%2C0%29)
![x = \sqrt{15}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%7B15%7D%20)
or
![x = - \sqrt{15}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Csqrt%7B15%7D%20)