If a number is a multipule of 6 then it is a multiplule of 2 AND 3
if a number is a multiplule of 2 then the last digit should be divisible by 2 (ie, 0,2,4,6,8)
if a number is divisible by 3, then the sum of its digits is divisble by 3
try each
A. 333
last number is not divisible by 2 so not divisible by 6
B. 882
2 is divisible by 2
8+8+2=18
18/3=6
divisible by 6 yes
C. 424
4 is disibielbe by 2
4+2+4=10
10/3=not a whole number so not divisible by 6
D. 106
6 is divisible by 2
1+0+6=7
7/3= not a whole number so not divibislb eby 6
answer is B
Answer:
Natalie's age is 14
Sasha's age is 17
Step-by-step explanation:
Let
Sasha's age be "s", and
Natalie's age be "n"
<u>Sum of Sasha and Natalie is 31:</u>
s + n = 31
<u>Twice Natalie is 11 more than Sasha:</u>
2n = s + 11
We ca solve this equation for s first:
s = 2n - 11
We put this into first equation and solve for n first:
s + n = 31
2n - 11 + n = 31
3n = 31 + 11
3n = 42
n = 42/3 = 14
Natalie's age is 14
Also, s = 2n - 11
s = 2(14) - 11
s = 28 - 11
s = 17
Sasha's age is 17
That’s the answer for that question
Answer:
the area of the hexagon is approx. 187.1 in²
Step-by-step explanation:
Picture this regular polygon as being a hexagon made up of six equilateral triangles of side 12 in. We find the area of one such triangle and then multiply that by 6 to obtain the total area of the hexagon.
One such equilateral triangle has three sides all of length 12 in, and all the interior angles are 60°. The height of one such triangle is
h = (12 in)sin 60°, or
√3
h = (12 in) -------- = 6√3 in
2
So, with base 12 in and height 6√3 in, the area of one such equilateral triangle is
A = (1/2)(12 in)(6√3 in) = 36√3 in²
and the total area of the hexagon is 6(36)√3 in², or approx. 187.1 in²
