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3 years ago

HELP PLEASE ITS GEOMETRY 17. If m∠EBD = 4x + 16 and m∠DBC = 6x + 4, find m∠EBD.

Mathematics

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

$m\angle EBD=40^{\circ}$

Step-by-step explanation:

We have been given a diagram. We are asked to find the measure of angle EBD.

Since ray BD is angle bisector of angle EBC, so measure of angle EBD will be equal to measure of angle DBC.

$m\angle DBC=m\angle EBD$

$6x+4=4x+16$

$6x-4x+4=4x-4x+16$

$2x+4=16$

$2x+4-4=16-4$

$2x=12$

$\frac{2x}{2}=\frac{12}{2}$

$x=6$

To find measure of angle EBD, we will substitute $x=6$ in expression $4x+16$ as:

$m\angle EBD=4(6)+16$

$m\angle EBD=24+16$

$m\angle EBD=40$

Therefore, measure of angle EBD is 40 degrees.

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3x > -3 Thanks very much

OverLord2011 [107]

Answer:

Answer is below

Step-by-step explanation:

Divide both sides by 3.

$\frac{3x}{3}>\frac{-3}{3} \\x>-1$

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3 years ago

Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,

Arisa [49]

ANSWER

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

EXPLANATION

The given function is

$y = {x}^{2} \cos(x)$

We take natural log of both sides;

$ln(y) = ln({x}^{2} \cos(x) )$

Recall and use the product rule of logarithms.

$ln(AB) = ln(A ) + ln(B)$

This implies that:

$ln(y) = ln({x}^{2} ) + ln( \cos(x) )$

$ln(y) = 2 ln({x} ) + ln( \cos(x) )$

We now differentiate implicitly to obtain;

$\frac{ {y}^{'} }{y} = \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) }$

Multiply through by y,

${y}^{'} = y( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) })$

Substitute y=x²cosx to obtain;

${y}^{'} = {x}^{2} \cos(x) ( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) } )$

Expand:

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

7 0

3 years ago

Which relationship is a direct variation?

vekshin1

D because each y value is obtained by multiplying x by -2
y = -2x which is direct variation.

8 0

3 years ago

Read 2 more answers

Please Answer Quick 65 Points ! !

NeTakaya

The correct answers are:

The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.

The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.

Further explanation:

Given equations are:

2x-y = -5

x+3y = 22

We have to check whether the given statements are true or not. In order to find that we have to put the points in the equations

Putting the point in 2x-y = -5

$2x - y = -5\\2(7) -19 = -5\\14-19 = -5\\-5 = -5$

Putting the point in x+3y=22

$7 + 3 (19) = 22\\7 + 57 = 22\\64 \neq 22$

The point satisfies the first equation but doesn't satisfy the second. So,

1. The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.

This statement is true as the point satisfies the first equation

2. The ordered pair (7, 19) is a solution to the second equation because it makes the second equation true.

This Statement is false.

3. The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.

This statement is true.

4. The ordered pair (7, 19) is a solution to the system because it makes both equations true.

This statement is false as the ordered pair doesn't satisfy both equations.

Keywords: Solution of system of equations, linear equations

Learn more about solution of linear equations at:

#LearnwithBrainly

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3 years ago

How to do linear functions using the table ?

Ira Lisetskai [31]

Answer:

-8 = m-2+b

-2 = m-0+b

4 = m2+b

10 = m4+b

Step-by-step explanation:

You just put them in y = mx+b format

3 0

3 years ago