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2 years ago

I dont mnow whats going on

Mathematics

2 answers:

Vlad1618 [11]2 years ago

8 0

Answer:

∠DEC = 83º

Step-by-step explanation:

∠BAC and ∠ABC combine is 105º.

∠ACB is 75º.

∠ECD is 75º.

180º-75º-22º=83º

Gre4nikov [31]2 years ago

5 0

Isn’t it the same degree as BAC

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3 years ago

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Levart [38]

1+3^2 = 1+9 = 10

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3 years ago

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Explain the steps involved in adding two rational<br> expressions.<br> DONE

Helen [10]

Answer

Step-by-step explanation: example

5/(X+2). + 2/(X+1)

Common denominator. Is both (X+2)(X+1)

So the first fraction needs (X+1) since it already has (X+2) the second fraction needs ( X+2)

5(X+1). / (X+2)((X+1) +. 2/(X+2)/(X+1)

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3 years ago

The quotient of m and 7.

Firdavs [7]

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2 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

2 years ago